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3 years ago

The graph of y = f(x) is shown below. Determine the value of x when f(x) = 2?

Mathematics

1 answer:

olga_2 [115]3 years ago

4 0

The value of x when f(x) = 2 is 0.

When you replace f(x) with 2 you get y = 2.

Thus, you graph y = 2 and you get the following image below.

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A conical-shaped umbrella has a radius of 0.4 m and a height of 0.45 m. Calculate the amount of fabric needed to manufacture thi

bonufazy [111]

Answer:

The correct answer will be "0.756596 m²".

Step-by-step explanation:

The given values are:

The radius of an umbrella,

r = 0.4 m

The height of an umbrella,

h = 0.45 m

As we know,

The lateral surface of an umbrella will be:

⇒ $\pi r\sqrt{r^2+h^2}$

On substituting the values, we get

⇒ $\pi \times 0.4\sqrt{(0.4)^2=(0.45)^2}$

⇒ $0.756596 \ m^2$

So that the amount of fabric needed will be "0.756596 m²".

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3 years ago

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denis-greek [22]

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Step-by-step explanation: IDK?

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3 years ago

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3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

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3 years ago