There will be 130 nickels and 90 dimes. 100 nickels is 5 dollars. 90 dimes are 9 dollars. And then there will be 30 left. 30 dimes isn’t 1.50$ bur 30 nickels is 1.50$ so you add the 30 to the nickels and it’ll be exactly 15.50$.
One month = 5000
Number of months before the spark plugs need to change :
15000 ÷ 5000 = 3
The sparks can last 3 months before it needs to be changed.
Number of times it need to change in a year = 12 ÷ 3 = 4
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Answer : It needs to be change 4 times a year.
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The answer to your is 100 volts
Answer:
0.4%
Step-by-step explanation:
In this case, because the coins have been replaced, the final probability would be multiplying the same probability six times (or raising it to exponent 6.). In other words, the probability of a dime coming out.
This probability would be the amount of dimes divided by the total number of coins, as follows:
Total coins = 10 + 8 + 2 = 20 coins.
So the probability would be: 8/20 = 2/5
The final probability would then be:
(2/5) ^ 6 = 0.004
In other words, the probability of this event occurring 6 times in a row is 0.4%
Answer:
4/7
Step-by-step explanation:
Using the hint, we have an original fraction of x/(x+3). The given manipulations and relations can be used to find the value of x, and the original fraction.
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<h3>adding 2 to each term</h3>
The new fraction is ...
<h3>new value</h3>
Apparently, the new value of this fraction is 2/3. We can use this to find the value of x.
The original fraction is ...
4/(4+3) = 4/7
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<em>Alternate solution</em>
In the ratio 2/3, the numerator is twice the difference between the denominator and numerator. 2 = 2(3 -2)
The problem statement tells us the difference between the numerator and denominator is 3. That is not changed by adding the same number to each. This means the fraction equivalent to 2/3 is (2·3)/(3·3) = 6/9. Subtracting 2 from each of the numerator and denominator gives the original fraction:
(6-2)/(9-2) = 4/7
