The answer on E2020 is A: Rolling a six-sided number cube 24 times and recording if a 4 comes up.
Answer: Vertex (-2,-15) and therefore the axis of sym will be -2
Step-by-step explanation: Using -b/2a you can deduce that 4x^2 is a, 16x is b and 1 is c. So -b/2a = -16/8 = -2. Then you plug -2 for y and yu should get -15. Then x will be your axis of symetry to x=-2
Note: √a * √a = a
√a * √b = √ab
(√2 + √10)² = (√2 + √10)(√2 + √10)
= √2(√2 + √10) + √10(√2 + √10)
= √2*√2 + √2*√10 + √10*√2 + √10*√10
= 2 + √20 + √20 + 10
= (2 + 10) + (√20 + √20)
= 12 + 2√20
√20 = √(4 *5) = √4 * √5 = 2√5
= 12 + 2√20 = 12 + 2(2√5)
= 12 + 4√5
Answer:
see below
Step-by-step explanation:
some of your answers that you currently have are wrong, I'll note those mistakes below
- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio
5x+15 = 5(x+3), not (x+3)(x+5)
ie 
we see that 10x can divide the numerator in a whole number ratio
= 10x(x+2), not (x+2)(x+10)
second mistake: the first binomial expansion is incorrect.
you have the expansion formula right, but you added terms wrong, go look at it again
3. x^2+3x+2/ x^2+5x+6
(x+1)(x+2)/(x+3)(x+2)
(x+1)/(x+3)
4. (x^2+6x+8)/(x^2-16)
(x+4)(x+2)/(x+4)(x-4)
(x+2)/(x-4)
5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator
6. (x^4y^6)^2
(x^4y^6)(x^4y^6) = 
remember that (x^a)(x^b) = x^(a+b)
or remember that (x^a)^b = x^ab