Re-write the quadratic function below in Standard Form y = -(x – 3)2 +8

Mathematics

1 answer:

lisov135 [29]3 years ago

4 0

Answer:

y = -x² + 6x - 1

General Formulas and Concepts:

Algebra I

Standard Form: ax² + bx + c = 0
Expanding by FOIL (First Inside Outside Last)
Combining like terms

Step-by-step explanation:

Step 1: Define equation

y = -(x - 3)² + 8

Step 2: Rewrite

Expand [FOIL]: y = -(x² - 6x + 9) + 8
Distribute -1: y = -x² + 6x - 9 + 8
Combine like terms: y = -x² + 6x - 1

You might be interested in

A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent

BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

Solution also leaves the tank at a rate of 2L/hr, therefore in x hours, the amount of water that have left the tank = 2x

Hence the amount of water present in the tank at x hours is given as:

3 + 3x - 2x = 3 + x

The time taken to full the tank can be gotten from:

3 + x = 6

x = 6 - 3

x = 3 hr

$\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\ \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg$