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lisabon 2012 [21]
3 years ago
7

Three less than two times a number is 55. What is the number ?

Mathematics
2 answers:
vampirchik [111]3 years ago
6 0
2x-3=55
You solve the equation as follows: 
2x-3=55
    -3   -3
2x=52
/2    /2
x= 26
The number is 26
Aloiza [94]3 years ago
5 0
29
2x29=58-3 =55
3-2x (x=29) =55
29x2=58-3
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3n^2=6-17n I need Vertex form please.
nasty-shy [4]

Answer:

3( n + \frac{17}{6} )² - \frac{361}{12} = 0

Step-by-step explanation:

3n² = 6 - 17n ⇔ 3n² + 17n - 6 = 0

3( n² + 2 × \frac{17}{6} n + ( \frac{17}{6} )² - ( \frac{17}{6} )² - 2 ) = 0

3( n + \frac{17}{6} )² - 3 × \frac{289}{36} - 6 = 0

3( n + \frac{17}{6} )² - \frac{361}{12} = 0

8 0
2 years ago
The circumference of a circle is 18 pi feet. What is the area in terms of pi?
Nastasia [14]

Answer:

I am not sure if this is right but the answer is

The area of a circle with circumference 18π is 254.5

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2 years ago
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diamong [38]

Answer:

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6 0
2 years ago
A list of numbers is given <br><br><br> 32,16,8,4,2,1<br><br> Write a rule for the pattern
Sphinxa [80]
It is subtracting the current number by 1/2    OR you can divide by 2. each time.

32 / 2= 16
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Hope this helped!
5 0
3 years ago
Read 2 more answers
Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp
Maslowich

If p(3-2i)=0, then complex number 3-2i is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated 3+2i is also a root of polynomial.

Then the polynomial will be of a form

p(x)=(x-(3-2i))(x-(3+2i))(x-a).

Since p(0)=-52, then

-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.

Therefore,

p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.

3 0
2 years ago
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