Set up an equation and solve for this problem.

1 answer:

7 0

Your equation might look like this,
Since the ticket is $8, and her budget is 50, your gonna have to divide.
Then the remaining answer would be, 6.25.
So, your equation= $50/$8=6.25
Your answer is 6, 6 tickets can be bought with the remainder of 0.25 cents.

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A truck is used to transport gravel. The box on the truck is a rectangular prism 11 ft long, 7 ft wide and 4 ft high. The box do

chubhunter [2.5K]

Answer:

308 cubic feet

Step-by-step explanation:

The box on the truck has dimensions 11 ft by 7 ft by 4 ft.

The volume of the box is:

V = L * W * H

V = 11 * 7 * 4

V = 308 cubic feet

The truck can transport 308 cubic feet of gravel.

8 0

3 years ago

LM is the midsegment of trapezoid ABCD. AB= x + 8, LM = 4x + 3, and DC = 187. What is the value of x?

beks73 [17]

$\frac{|DC|+|AB|}{2}=|LM|\\\\|AB|=x+8;\ |LM|=4x+3;\ |DC|=187\\\\substitute:\\\\\frac{187+x+8}{2}=4x+3\ \ \ \ /\cdot2\\\\195+x=8x+6\ \ \ /-195;\ /-8x\\\\-7x=-189\ \ \ /:7\\\\\underline{\underline{x=27}}$

5 0

3 years ago

Sec squared 55 - tan squared 55

sergejj [24]

Answer:

sec squared 55 – tan squared 55 = 1

Explanation:

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$