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3 years ago

If you have a decimal answer, round to the nearest tenth! x/-4−3=0

1 answer:

5 0

X = -12 !!

so first rewrite the fraction
multiply both sides
move the constant to the right
change the signs
then you have your solution

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ASAP PLEASE please please

Aleksandr [31]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

$\qquad \sf \dashrightarrow \: \cfrac{1}{b} + 10 = \cfrac{9}{b} + 7$

$\qquad \sf \dashrightarrow \: \cfrac{9}{b} - \cfrac{1}{b} = 10 - 7$

$\qquad \sf \dashrightarrow \: \cfrac{8}{b} = 3$

$\qquad \sf \dashrightarrow \: b = \cfrac{8}{3}$

5 0

2 years ago

Read 2 more answers

Select the two values of x that are roots of this equation 3x^2 + 1 =5x

Zina [86]

Answer:

x = 1.434 and x=0.232

Step-by-step explanation:

To find the root of the equation stated above we need to:

(1) Write the polynomial equation with zero on the right hand side:

$3x^{2} + 1 = 5x$ ⇒ $3x^{2} -5x + 1 = 0$

(2) Divide the whole equation by 3

$3x^{2} -5x + 1 = 0$ ⇒ $x^{2} -\frac{5}{3}x + \frac{1}{3}= 0$

(3) Use the quadratic formula to solve the quadratic equation:

The quadratic formula states that the two solutions for a quadratic equation is given by:

$\frac{-b±\sqrt{b^{2} - 4ac}}{2a}$ (1)

In this case, a = 1, b = $-\frac{5}{3}, c= \frac{1}{3}$

Substituiting a, b and c in equation (1) We get:

$\frac{-\frac{5}{3}±\sqrt{(-\frac{5}{3})^{2} - 4(1)(\frac{1}{3})}}{2(1)}$ (1)

The two solutions are:

x = 1.434 and x=0.232

8 0

3 years ago

Write an inequality to describe the possible values of x.

Papessa [141]

Answer:

Step-by-step explanation:

x<9+7, and x+7>9

solve

x<16

x>2

2<x<16

6 0

3 years ago

Arrange these numbers in order from least to greatest 0.1, 1, -1,

LenaWriter [7]

Answer:

-1, 0.1, 1

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3 0

3 years ago

Read 2 more answers

Help me on this one please

shepuryov [24]

Answer:

The equation is set up wrong

Step-by-step explanation:

$9^{2} +b^{2} =15^{2}$

3 0

3 years ago