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VashaNatasha [74]
3 years ago
11

Use (x-3)^2 -6 to solve x^2-6x+3=0 leave your answer in surd form

Mathematics
1 answer:
Mrac [35]3 years ago
8 0

Answer:

x=3\pm\sqrt{6}

Step-by-step explanation:

(x-3)^2-6=0

(x-3)^2=6

x-3=\pm\sqrt{6}

x=3\pm\sqrt{6}

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What are the roots of the equation 16x2 + 40x + 27 = 0 in simplest a + bi form?
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Answer:

  -5/4 +i(√2)/4 and -5/4 -i(√2)/4

Step-by-step explanation:

I find simplest form to be easier to get to if the leading coefficient is 1. Dividing by 16, we have ...

  x^2 +5/2x +27/16 = 0

Completing the square by adding and subtracting the square of half the x-coefficient, we get ...

  (x^2 +5/2x +25/16) +27/16 -25/16 = 0

  (x +5/4)^2 = 2/16

Subtracting 2/16, taking the square root, and subtracting 5/4 gives ...

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The roots are -5/4 +i(√2)/4 and -5/4 -i(√2)/4.

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2 years ago
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