Im very confused,I have no idea if im suppose to mutiplty it or no

If f(x)=4(3x-5), find f^-1(x)

Margaret [11]

Answer:

f^-1(x) = (x+20) / 12

Step-by-step explanation:

f(x) = 4(3x-5)

Let y be the image of f.

y = 4(3x-5)

y = 12x-20

y+20 = 12x

x = (y+20) / 12

f^-1(y) = (y+20) / 12, so

f^-1(x) = (x+20) / 12

3 0

2 years ago

Ivan sold 31 boxes of oranges on Friday and 29 boxes on Saturday during a citrus sale. There were 10 oranges in each box. How ma

ycow [4]

Answer:

600

Step-by-step explanation:

31 plus 29 is 60

60 x 10 = 600

7 0

3 years ago

PLEASE HELP!! URGENT!!!! UNIT TEST!!!!

slavikrds [6]

ANSWER

$y=-\frac{4}{3}x+\frac{16}{3}$

Or

$3y+4x=16$

EXPLANATION

Let us find the gradient of the line:

$-3x+4y=4$ by rewriting it in the slope intercept form.

$\Rightarrow 4y=3x+4$

We divide through by 4 now;

$\Rightarrow y=\frac{3}{4}x+1$

This is now in the form;

$y=mx+c$

where

$m=\frac{3}{4}$ is he slope.

This implies that the slope of the line that is perpendicular to this line will be the negative reciprocal of $m=\frac{3}{4}$ .

Thus the perpendicular line has slope,

$m=\frac{-1}{\frac{3}{4}}= -\frac{4}{3}$ .

Let the perpendicular line have equation,

$y=mx+c$

When we substitute the slope we have;

$y=-\frac{4}{3}x+c$

We substitute the point. $(4,0)$ to find c.

$0=-\frac{4}{3}(4)+c$

$0=-\frac{16}{3}+c$

$\frac{16}{3}=c$

We substitute c to obtain;

$y=-\frac{4}{3}x+\frac{16}{3}$

Or

$3y+4x=16$

7 0

3 years ago

Read 2 more answers

On the number line below the Numbers eight and B are the same distance from zero what is a plus B explain how you know?

Igoryamba

A = 1
b = -1

a + b =
1 + (-1) =
1 - 1 =
0....so a + b = 0

additive inverse property states that every real number added to its additive inverse (or opposite) will equal zero.

3 0

3 years ago

A sports news station wanted to know whether people who live in the North or the South are bigger sports fans. For its study, 17

Free_Kalibri [48]

Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).

<h3>What are the mean and the standard error for each sample?</h3>

Considering the data given:

$\mu_S = 3.8, n = 175, s_S = \frac{1.7}{\sqrt{175}} = 0.1285$

$\mu_N = 4.8, n = 152, s_N = \frac{1.2}{\sqrt{152}} = 0.0973$

<h3>What is the mean and the standard error for the distribution of differences?</h3>

The mean is the subtraction of the means, hence:

$\overline{x} = \mu_S - \mu_N = 3.8 - 4.8 = -1$

The standard error is the square root of the sum of the variances of each sample, hence:

$s = \sqrt{s_S^2 + s_N^2} = \sqrt{0.1285^2 + 0.0973^2} = 0.1612$

<h3>What is the confidence interval?</h3>

It is given by:

$\overline{x} \pm zs$

We have a 95% confidence interval, hence the critical value is of z = 1.96.

Then, the bounds of the interval are given as follows:

$\overline{x} - zs = -1 - 1.96(0.1612) = -1.3$

$\overline{x} + zs = -1 + 1.96(0.1612) = -0.7$

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0

2 years ago