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mojhsa [17]
3 years ago
13

What is the area of the sector of the circle when the radius is 10 and the shaded part is 45 degrees

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
7 0

Answer:

We are solving for the area so; A=134.16

Step-by-step explanation:

Zarrin [17]3 years ago
7 0

Here is the formula for finding area of a sector:

A = \pi r^{2} × θ° ÷ 360°

where theta is the angle of the sector you wish to find, and r is the radius of the circle.

Substitute the numbers in and you get:

\frac{25\pi }{2}  unit ^{2}

You should find 39.26991 as your answer (or any number rounded according to the value of pi)

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Solve for y please help
ss7ja [257]

Answer:

The answer is (-16.6)

Step-by-step explanation:

y/2 ≥ -8.3

y ≥ (-8.3) × 2

y ≥ -16.6

Thus, The value of y is (-16.6)

<u>-TheUnknownScientist 72</u>

7 0
2 years ago
A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s
yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2}  = \frac{1 \pm 9 }{-0.4}

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0
3 years ago
X+3y=14<br> y=3x-14<br> Solving systems using substitution <br> How do i do this?
Free_Kalibri [48]
X + 3y = 14
x + 3(3x - 14) = 14
x + 9x - 42 = 14
10x - 42 = 14
<u>      + 42 + 42</u>
       <u>10x</u> = <u>56</u>
        10     10
           x = 5.6
5.6 + 3y = 14
<u>- 5.6         - 5.6</u>
         <u>3y</u> = <u>8.4</u>
          3       3
           y = 2.7
     (x, y) = (2.7, 5.6)
6 0
4 years ago
Read 2 more answers
Determine the probability of a negative result for a batch of size 10 if the positivity rate
Vlad1618 [11]

The probability of a negative result for a batch will be "0.3487".

Given values are:

Positivity rate,

  • p = 10% or, 0.1

Batch size,

  • n = 10

Now,

The probability of negative result will be:

→ P (batch \ negative) = (1-p)^n

By substituting the values, we get

→                               =(1-0.1)^{10}

→                               = (0.9)^{10}

→                               = 0.3487

Thus the answer above is right.

Learn more about the probability here:

brainly.com/question/17927863

8 0
3 years ago
Tara ran the 1600 M event at a constant speed in 5 minutes and 20 seconds. what was her speed
ollegr [7]

5 m/sec or 300m / min

using speed = \frac{distance}{time}

change 5 min 20 sec to seconds = (5 × 60) + 20 = 320 sec

speed = \frac{1600}{320} = 5m / second or

speed = 60 × 5 = 300m / minute



4 0
3 years ago
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