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kicyunya [14]
3 years ago
5

HELP PLEASE :/ not too good in geometry sadly

Mathematics
2 answers:
Reil [10]3 years ago
5 0

Answer:

3rd option

Step-by-step explanation:

tanB = \frac{opposite}{adjacent} = \frac{AC}{BC} = \frac{2x+4}{x+3}

My name is Ann [436]3 years ago
5 0
The answer is hope this helps
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Which of the following expressions does not represent “increase a quantity n by 25%”?
nexus9112 [7]

Option C) 125n is the expression that does not represent “increase a quantity n by 25%

<u>Step-by-step explanation:</u>

The given expressions are for the quantity n which is increased by 25%.

  • Let us consider that n = 100.
  • The increase of n by 25 % is equal to 125.
  • Check for each options by substituting n=100 and the expression gives 125 or not.
  • Check which option does not represent the condition (increase of n by 25%)

<u>Option A) n + 0.25n </u>

Put n = 100,

⇒ 100 + 0.25(100)

⇒ 100 + 25

⇒ 125

So, option A) represents the given condition.

<u>Option B) (1 + 0.25)n</u>

Put n = 100,

⇒ (1+0.25) 100

Multiply 100 with each terms inside the bracket.

⇒ 100 + 25

⇒ 125

So, option B) represents the given condition.

<u></u>

<u>Option C) 125n</u>

Put n = 100,

⇒ 125 × 100

⇒ 12500

So, option C) does not represents the given condition.

<u>Option D) 1 1/4 n</u>

Put n = 100,

Convert the mixed fraction to proper fraction

⇒ (5/4) n

⇒ (5/4) 100

⇒ 500 / 4

⇒ 125

So, option D) represents the given condition.

<u></u>

<u></u>

7 0
4 years ago
What is the value of x?
yuradex [85]

Answer:

x = 12

Step-by-step explanation:

7 0
3 years ago
Assume that there are 56 students in this class. what is the probability that at least two students share a? birthday
navik [9.2K]

P(at least 2 students have the same birthday)= 1- P(no 2 students have the same birthday)

Because P(A)=1-P(A'), where A is an event, and A' the complement of that event.

P(no 2 students have the same birthday)=

\frac{365}{365}* \frac{364}{365}*\frac{363}{365}*\frac{362}{365}*... \frac{310}{365}

think of the problem as follows. We have an urn of balls, numbered from 1 to 365 (the number of the days of the year. 

What is the probability of picking 56 different numbered balls, with replacements?

The first one can be any of the 365

the second any of 364 (since one selection has already been made)

the third any of the 363
.
.
and so on

the 56th selection is one of 310 left


Answer: 

\frac{365}{365}* \frac{364}{365}*\frac{363}{365}*\frac{362}{365}*... \frac{310}{365}


4 0
3 years ago
Henry is making bread. Henry calculates the rate at which the dough rises. He finds that the volume of the dough in cubic inches
uranmaximum [27]

Answer: the volume of the dough is dependant variable and minutes since the dough was made is independant

Step-by-step explanation:

Just took the quiz and got it correct, hope this helps! :)

7 0
3 years ago
Is 5 to 4 and 35 to 28 porportional
kirill115 [55]
Yes, it is
hope this helped
7 0
3 years ago
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