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CaHeK987 [17]
3 years ago
12

PLEASE HELP, THANK YOU! :)

Mathematics
1 answer:
elena-s [515]3 years ago
8 0

Steps to solve:

-4z + 4 + 12z = 3z + 4 + 5z

~Combine like terms

8z + 4 = 8z + 4

~Subtract 4 to both sides

8z = 8z

~Divide 8 to both sides

0 = 0

All real numbers are solutions.

Set builder notation: {x | R}

This is an identity since every value can be a solution to the equation.

Best of Luck!

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Find the slope of the line passes through the pair of points (-5.5,6.1), (-2.5,3.1)
skad [1K]
The answer would be C.

If you do -5.5 + 2.5 over 6.1 - 3.1 it would be -3 over 3 which is equal to -1.

You could also do -2.5 + 5.5 over 3.1 - 6.1. It would be 3 over -3 which is also equal to -1.
7 0
3 years ago
How do you do this question help PPPPPLLLLLZZZZZ
My name is Ann [436]
It is just 4 x 4 for each and everyside
5 0
4 years ago
There are 52 cards in a deck. Each card contains a letter or a number. Theo selects a card at random, records the letter or numb
pav-90 [236]
<h3>Answer:  16</h3>

=======================================================

Explanation:

A = ace

Q = queen

Theo's results are: 5, A, 2, 8, Q, 9

He got four numbers (5,2,8,9) out of 6 cards total. The empirical probability of getting a number is 4/6 = 2/3. Multiply this with the 24 trials to get (2/3)*24 = 48/3 = 16.

We expect Theo to get roughly 16 numbers if he conducted 24 trials. This is not guaranteed because of the nature of the random process. Though it should be fairly close to 16 assuming that we stick with that empirical probability (i.e. the amount of number cards is roughly 2/3 of the deck).

4 0
2 years ago
A car is bought for £1500 but depreciates in value at the rate of 8% per year. Calculate how much the car is worth after 5 years
julsineya [31]

Answer:

600

Step-by-step explanation:

PRT divided by 100

1500*8*1/100

=120

120*5 for 5 years

,=600

4 0
3 years ago
Please help with differential equations
alexira [117]

4.15

y'+\dfrac 2xy=x^3

is a linear ODE; multiply both sides by the integrating factor x^2:

x^2y'+2xy=x^5

Now the left side can be condensed as the derivative of a product:

(x^2y)'=x^5

Integrate both sides and solve for y to get

x^2y=\dfrac{x^6}6+C\implies y=\dfrac{x^4}6+\dfrac C{x^2}

Given that y(1)=-\frac56, we find

-\dfrac56=\dfrac16+C\implies C=-1

and so the particular solution is

\boxed{y(x)=\dfrac{x^4}6-\dfrac1{x^2}}

5.15

2y^2\,\mathrm dx+(x+e^{1/y})\,\mathrm dy=0

You may be tempted to write this as an ODE in y(x), but the ODE in x(y) is much easier to solve, since it's linear. Solve for \frac{\mathrm dx}{\mathrm dy}=x' and rearrange the terms:

\dfrac{\mathrm dx}{\mathrm dy}=-\dfrac{x+e^{1/y}}{2y^2}\implies x'+\dfrac x{2y^2}=-\dfrac{e^{1/y}}{2y^2}

Multiply both sides by the integrating factor e^{-1/(2y)}, then solve for x:

e^{-1/(2y)}x'+\dfrac{e^{-1/(2y)}}{2y^2}x=-\dfrac{e^{1/(2y)}}{2y^2}

\left(e^{-1/(2y)}x\right)'=-\dfrac{e^{1/(2y)}}{2y^2}

e^{-1/(2y)}x=e^{1/(2y)}+C

x=e^{1/y}+Ce^{1/(2y)}

Given that y=1 when x=e, we have

e=e+Ce^{1/2}\implies C=0

so the particular solution is

\boxed{x(y)=e^{1/y}}

or, by solving for y,

\boxed{y(x)=\dfrac1{\ln x}}

6.15

y'-y=2xy^2

Dividing through both sides by y^2 lets us write the equation in Bernoulli form:

y^{-2}y'-y^{-1}=2x

Substitute v=y^{-1}, so that v'=-y^{-2}y'. Then we get an ODE that is linear in v:

-v'-v=2x\implies v'+v=-2x

Multiply both sides by the integrating factor e^x:

e^xv'+e^xv=(e^xv)'=-2xe^x

Integrate both sides and solve for v, then solve for y:

e^xv=-2e^x(x-1)+C

v=-2(x-1)+Ce^{-x}

\dfrac1y=-2(x-1)+Ce^{-x}

Given that y(0)=\frac12, we find

2=2+C\implies C=0

so the particular solution is

\dfrac1y=-2(x-1)=2-2x\implies\boxed{y(x)=\dfrac1{2-2x}}

4 0
3 years ago
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