WILL MARK BRAINLIEST! What are the coordinates of point P?

Mathematics

1 answer:

PSYCHO15rus [73]2 years ago

7 0

B negative 2 and negative 4.5

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If the measure of angle 1 is 110 degrees and the measure of angle 3 is (2 x + 10) degrees, what is the value of x?

user100 [1]

Answer:

Correct option is

∘

,90

∘

,90

∘

Let AB and CD be two lines Intersecting at O, such that, ∠AOD=90

∘

Now, ∠AOD=∠COB=90

∘

(Vertically opposite angles)

⟹∠AOD+∠DOB=180

(Angles on a straight line)

⟹90+∠DOB=180

∠DOB=90

∘

∠DOB=∠AOC=90

∘

(Vertically opposite angles)

Thus, all angles are 90

∘

7 0

2 years ago

The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y

Lelechka [254]

Given the next quadratic function:

$y=2x^2+3x-2$

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

$x_V=\frac{-b}{2a}$

where a and b are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

$\begin{gathered} x_V=\frac{-3}{2\cdot2} \\ x_V=-\frac{3}{4}=-0.75 \end{gathered}$

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

$\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}$

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get: