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ella [17]
3 years ago
10

-25 - 30 + 2 = pls help

Mathematics
1 answer:
Galina-37 [17]3 years ago
5 0

Answer:

7

Step-by-step explanation:

Do addition first, so 30 plus 2, and then subtract, 32 minus 25. It is seven.

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A mountain bike originally priced at $929.00 is up for sale at a discount of 12%. What is the price of the mountain bike after t
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Answer:

Step-by-step explanation:

817.52 should be correct

4 0
2 years ago
(Q6) Decide if the function is an exponential function. If it is, state the initial value and the base. y= -4.8·4^x
topjm [15]

Answer:

D

Step-by-step explanation:

Exponential equation takes the form  y=a*b^x  where

  1. a is the initial value ( a ≠ 0), and
  2. b is the base ( b ≠ 1)

The equation given in the problem can be written as  y=-4.8*4^x, so it is <em>an exponential equation, </em>  where a = -4.8 and b = 4.

Thus we can say that the initial value = -4.8 and the base is 4

The correct answer is  D

3 0
3 years ago
Is (1, 2) solution for this system of inequalities ?
diamong [38]

Answer:

MAYBE

Step-by-step explanation:

7 0
3 years ago
Find the accumulated value of an investment of 12,000 at 8 % compounded semiannually for 11 years
AleksAgata [21]
The "compound amount" formula is A = P(1+r/n)^(nt),
where P=original investment, r=interest rate as a decimal fraction; n=number of compounding periods, and t=number of years.

Then A = $12000 * (1+0.08/2)^(2*11) 
             = $12000(1.04)^(22)  =  $28,439.03  (answer)
4 0
3 years ago
Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
3 years ago
Read 2 more answers
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