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faltersainse [42]
4 years ago
9

Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the

upper tail defined by this value? ○ 0 ° ○ a.-NORMSINV(0.975) b.-NORM·S.INV(0.05) C.-NORM.S-INV(0.95) d.-NORMSINV(0.025)

Mathematics
1 answer:
fiasKO [112]4 years ago
6 0

Answer:

a) NORM.S.INV(0.975)

Step-by-step explanation:

1) Some definitions

The standard normal distribution is a particular case of the normal distribution. The parameters for this distribution are: the mean is zero and the standard deviation of one. The random variable for this distribution is called Z score or Z value.

NORM.S.INV Excel function "is used to find out or to calculate the inverse normal cumulative distribution for a given probability value"

The function returns the inverse of the standard normal cumulative distribution(a z value). Since uses the normal standard distribution by default the mean is zero and the standard deviation is one.

2) Solution for the problem

Based on this definition and analyzing the question :"Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the upper tail defined by this value?".

We are looking for a Z value that accumulates 0.975 or 0.975% of the area on the left and by properties since the total area below the curve of any probability distribution is 1, then the area to the right of this value would be 0.025 or 2.5%.

So for this case the correct function to use is: NORM.S.INV(0.975)

And the result after use this function is 1.96. And we can check the answer if we look the picture attached.

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Answer:

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The equation of line which passes through (4,3) and slope is 5/4

y-3=5/4(x-4)

4y-12=5x-20

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2 years ago
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3 years ago
Would the scale factor 4.2 enlarge,reduce,or preserve
Juli2301 [7.4K]

Hey there! I'm happy to help!

Let's look at what scale factors would be able to enlarge, reduce, and preserve first. We will use the point (1,1) as an example.

ENLARGE

When we talk about scale factors, both of our numbers of the ordered pair will be multiplied by that number. To make it bigger, we will multiply it by anything larger than a one, we could have a scale factor such as 2, 100, 579395. etc.!

Dilation of 2

(1,1)⇒(2,2)

REDUCE

To reduce our ordered pair, our scale factor must be a number greater than zero but less than one because it cannot switch quadrants, which is what would happen if we used negative numbers. Our reduced number must be greater than zero. We can use 1/2, 1/4, 1/100, 0.67 etc.

Dilation of 1/2

(1,1)⇒(0.5,0.5)

PRESERVE

What would we multiply an ordered pair by to make it stay the same? One of course! This is the only number that will keep it the same!

Dilation of 1

(1,1)⇒(1,1)

Now, let's think of any scale factor as X and see what rules it has to follow to be enlarging, reducing, or preserving.

ENLARGING SCALE FACTOR: X>1

REDUCING SCALE FACTOR: 0<X<1

PRESERVING SCALE FACTOR: X=1

So, where does 4.2 fall? Well, as you can see, 4.2 is greater than one, so this scale factor would make our point larger.

Therefore, 4.2 would enlarge.

I hope that this helps! Have a wonderful day!

8 0
3 years ago
Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time he will use the Same amount of plan
DanielleElmas [232]

Answer:

3 7/12 kg

He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time

Step-by-step explanation:

On sunday , sheldon bought 4 1/2 kg of plant food. He uses 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plants. b. Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will be need? Does he have enough left to do so.

Total plant bought = 4 1/2 kg

Strawberry = 1 2/3 kg

Tomato = 1/4 kg

Strawberry + tomato

= 1 2/3 + 1/4

= 5/3 + 1/4

= 20+3/12

= 23/12 kg

Total remaining after Sunday

= Total - used

= 4 1/2 - 23/12

= 9/2 - 23/12

= 54-23/12

= 31/12

= 2 7/12 kg

Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time.

Strawberry = 2 × 1 2/3

= 2 × 5/3

= 10/3 kg

Tomato = 1 × 1/4

= 1/4 kg

Total plant needed to feed strawberry two more times and tomato 1 more time

= 10/3 kg + 1/4 kg

= 40+3/12

= 43/12 kg

= 3 7/12 kg

He will need 3 7/12 kg of plant

He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time

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Answer:Angela paid 679,05 for the couch

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722,5-43,45=679,05

8 0
3 years ago
Read 2 more answers
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