Can u plz show work? Thanks so much! It's an easy problem.
1 answer:
The answer is D.
√-6(√-4 - √3) =
<span>
√-6 = </span>√-1√6 = i√6 Express <span>√-6 in terms of i
</span>i√6(√-4 - √3)
√-4 = √-1√4 = i √4 Express <span>√-4 in terms of i
</span>i√6(i√4 - √3)
√4 = 2 simplify radicals
i√6(2i - √3)
√6(2i - √3) = 2i√6 - 3√2 Distribute √6 over 2i-√3
i(2i√6 - 3√2)
i(2i√6 - 3√2) = -3i√2-2√6 Distribute i over (2i)√6 - 3√2
-3i√2 - 2√6
factor -1 from -3i√2 - 2√6
= -(2√6 + 3i√2) == -2√6 - 3i√2
hope that helps!
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