Answer:
Step-by-step explanation:
Answer:
1600
Step-by-step explanation:
b : g : total
9 : 7 : 16
difference-> 9-7=2
2u->100
1u-> 50
16u-> 1600
Answer:
81, 27, 48, 77
Step-by-step explanation:
The average speed of the student for his entire walk is equal to 1.5 m/s. Therefore, option (b) is correct.
What is the average speed?
The average speed of a body is calculated as the total distance traveled in a fixed interval of time. The average speed can be determined by dividing the total distance traveled by a body by the total time.
The average velocity is a single value if the object moves uniformly. Speed is a scalar quantity, it has no specified direction. The average speed has the S.I. unit the same as velocity i.e. m/s.
Given the distance covered by a student in first 80 sec = 100m
After stooping for 30sec again cover a distance of 200m in 90sec.
The total distance traveled by the student = 100 + 200 = 300m
The time taken by student to cover distance = 80 + 30 +90 = 200 sec
The average speed of the student = total distance/ total time taken
= 300/200 = 1.5 m/s
Therefore, the average speed of the student is equal to 1.5m/s.
Learn more about average speed, here:
brainly.com/question/12322912
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Answer:
![\left[\begin{array}{ccc}-32\\4\\20\\-36\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-32%5C%5C4%5C%5C20%5C%5C-36%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The product of a scalar times the matrix involves the product of that scalar times each of the elements of the matrix, resulting on the multiplication by "-4" of each of the four elements as shown below. These new product values end up being the new matrix elements.
![-4*\left[\begin{array}{ccc}8\\-1\\-5\\9\end{array}\right] = \left[\begin{array}{ccc}-32\\4\\20\\-36\end{array}\right]](https://tex.z-dn.net/?f=-4%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%5C%5C-1%5C%5C-5%5C%5C9%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-32%5C%5C4%5C%5C20%5C%5C-36%5Cend%7Barray%7D%5Cright%5D)
