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Tema [17]
3 years ago
12

4×(x+1)−5=11 NEED HELPPPP

Mathematics
1 answer:
AleksandrR [38]3 years ago
4 0
X=4 this is because 4 times (x+1)-5=11 the 1x then just turns to x because you can’t have a 1 next to x when it’s just one x.
4*(x+1)-5=11
4(x)-5=11
4x-5=11
+5=11
—————
4x=16
4. 4
———-
X=4
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WILL GIVE BRAINLIEST AND 100 POINT
Andre45 [30]

Answer:

9

Step-by-step explanation:

you find the percentage that is no, 2/8 would be 25% then take 25% of 36 to find the amount of students that are traveling.

8 0
3 years ago
What is the prime factorization of 440?
lawyer [7]

Answer:

I would say the correct answer is 2^3 • 5 • 11

Step-by-step explanation:

To find the prime factors, you start by dividing the number by the first prime number, which is 2. If there is not a remainder, meaning you can divide evenly, then 2 is a factor of the number. Continue dividing by 2 until you cannot divide evenly anymore. Write down how many 2's you were able to divide by evenly. Now try dividing by the next prime factor, which is 3. The goal is to get to a quotient of 1.Here are the first several prime factors: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29...

<u>Let's start by dividing 440 by 2 </u>

440 ÷ 2 = 220 -  No remainder! 2 is one of the factors!

220 ÷ 2 = 110 -  No remainder! 2 is one of the factors!

110 ÷ 2 = 55 - No remainder! 2 is one of the factors!

55 ÷ 2 = 27.5 - There is a remainder. We can't divide by 2 even anymore. Let's try the next prime number

55 ÷ 3 = 18.3333 - This has a remainder. 3 is not a factor.

55 ÷ 5 = 11 - No remainder! 5 is one of the factors!

11 ÷ 5 = 2.2 -There is a remainder. We can't divide by 5 evenly anymore. Let's try the next prime number

11 ÷ 7 = 1.5714 - This has a remainder. 7 is not a factor.

11 ÷ 11 = 1 - No remainder! 11 is one of the factors!

If we put all of it together we have the factors 2 x 2 x 2 x 5 x 11 = 440. It can also be written in exponential form as 2^3 x 5^1 x 11^1.

here is also the factor tree method : -

7 0
3 years ago
Help me with those two questions
Ksenya-84 [330]

Given:

A figure in which a transversal line intersect two parallel lines.

m\angle 2=4x+7, m\angle 7=5x-13, m\angle 5=68 and m\angle 3=3y-2.

To find:

The value of x and y.

Solution:

We know that, if a transversal line intersect two parallel lines, then

(1) Alternate exterior angles are equal.

(2) Same sided interior angles are supplementary. So their sum is 180 degrees.

In the given figure j and k are parallel lines and l is a transversal line.

From the given figure, it is clear that,

m\angle 2=m\angle 7                (Alternate exterior angles are equal)    

4x+7=5x-13

7+13=5x-4x

20=x

Therefore, the value of x is 20.

Now,

\angle 3+\angle 5=180     (Same sided interior angles are supplementary)

3y-2+68=180

3y+66=180

3y=180-66

y=\dfrac{180-66}{3}

y=\dfrac{114}{3}

y=38

Therefore, the value of y is 38.

3 0
3 years ago
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