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Art [367]
3 years ago
7

Pls help I really need to pass this if like for 4th quarter where I m pls help me

Mathematics
1 answer:
Tom [10]3 years ago
3 0

Answer:

✨Both will be the same✨

✨Step-by-step explanation:✨

there is 1 in each section 61 and 38

HOPE THAT HELPS

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The length of rectangle is 5 cm greater than its width. The perimeter is 106cm. Find the dimensions of the rectangle.
antiseptic1488 [7]

Width-24 Length-29

Two sides of the rectangle are 5 cm bigger than the other two. So you would add the two 5 cm together (10cm). If you take the 10 cm off you (106-10) you will get a square. Then all you have to do is divide 96 by 4 (24), and add back on the two 5cm from the beginning to the length (29).

4 0
3 years ago
Find CD, given that point G is the centroid of
andrey2020 [161]

let's recall that a Centroid in a triangle cuts the Medians into a 2:1 ratio, or namely CG : GD are in a 2: 1 ratio, we can also look at it that the side CD is 2/3 of CD whilst GD is 1/3 of CD, so

CG=\cfrac{2}{3}CD\implies 17.7=\cfrac{2CD}{3}\implies 3(17.7)=2CD \\\\\\ \cfrac{3(17.7)}{2}=CD\implies 26.55=CD

7 0
2 years ago
Find the value or measure. Round answers to the nearest tenth, as needed.
Leni [432]

Answer:

its 34

Step-by-step explanation:

its half of the center angles

3 0
2 years ago
Cassie's broker charges her a commission of $4.25 for every ten shares of stock bought or sold. Cassie buys 92 shares of Hyren A
olya-2409 [2.1K]

Answer:

2,850

Step-by-step explanation:

4.25 x 9 = 38.25

4.25 x 13 = 55.25

4.25 x 12 = 51

13.70 x 92 = 1260.4

3.28 x 130 = 426.4

8.06 x 126 = 1015.56

all totals would equal 2,846.86, which to the nearest would be $2,850

4 0
3 years ago
One parent is a cystic fibrosis carrier, and the other has
Marysya12 [62]

Answer:

A - 0%

B- 50%

C- 50%

D- 100%

Step-by-step explanation:

Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.

Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0
3 years ago
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