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azamat
3 years ago
8

Find the area of the triangle whose vertices are (2, 3); (-1, 0); (2, -4)...

Mathematics
1 answer:
Neko [114]3 years ago
8 0

Answer:

Area = 14.5

Step-by-step explanation:

Let's label the given coordinates A, B, C;

Thus;

A = (2, 3)

B = (-1, 0)

C = (2, -4)

From the coordinate geometry formula, the formula for area of a triangle with 3 vertices is;

Area = [Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)]/2

Area = [2(0 - (-4)) + (-1)(-4 - 3) + 2(3 - (-4))]/2

Area = 29/2

Area = 14.5

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A line contains the point (8, –5). If the slope of the line is 5/7, write the equation of the line using point-slope form.
IgorLugansk [536]

Answer: (y+5)=\frac{5}{7}(x-8)

Step-by-step explanation:

The point slope form of a line having slope m and point (a,b) is given by :-

(y-b)=m(x-a)

Given: A line contains the point = (8, –5)

The slope of the line =\frac{5}{7}

Now, the point slope form of a line having slope \frac{5}{7} and point (8,-5) is given by :-

(y-(-5))=\frac{5}{7}(x-8)\\\\\Rightarrow\ (y+5)=\frac{5}{7}(x-8)

Hence, the equation of the line =(y+5)=\frac{5}{7}(x-8)

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navik [9.2K]

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Step-by-step explanation:

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