From the standard normal tables, obtain P(z<1.95) = 0.9744 P(z<0.37) = 0.6443 P(z<1.32) = 0.9066 P(z<1.82) = 0.9656 P(z<1.05) = 0.8531 P(z<2.05) = 0.9798 P(z<0.03) = 0.5120 P(z<0.53) = 0.7019
Answers: Range of z Area -------------- --------------------------------------- a. 0 - 1.95 0.9744 b. 0 - 0.37 0.6443 c. 1.32 - 1.82 0.9656 - 0.9066 = 0.0590 d. 1.05 - 2.05 0.9798 - 0.8531 = 0.1267 e. 0.03 - 0.53 0.7019 - 0.5120 = 0.1899