1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bond [772]
3 years ago
5

Which relation is a function?

Mathematics
1 answer:
Step2247 [10]3 years ago
4 0
{(2, 3), (1, 5), (2, 7)} - NOT because 2->3 and 2->7
{(11, 9), (11, 5), (9, 3)} - NOT because 11->9 and 11->5
{(3, 8), (0, 8), (3, -2)} - NOT because 3->8 and 3->-2

{(-1, 5), (-2, 6), (-3, 7)} - YES
You might be interested in
Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

• 8 and \frac73 x^2 combine to make \frac{56}3 x^2

• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2

6 0
1 year ago
M is the midpoint of segment GR. G has coordinates (11,-5) and M is (4,-4) Find the coordinates of R
7nadin3 [17]

Answer:

  • (3, -3)

Step-by-step explanation:

<u>Given:</u>

  • G = (11,-5)
  • M = (4,-4)
  • R = ?

<u>Solution</u>

  • R(x, y)

<u>As per midpoint formula;</u>

  • 4 = (11 + x)/2  ⇒ x + 11 = 8 ⇒ x = 3
  • -4 = (-5 + y)/2 ⇒ y - 5 = -8 ⇒ y = -3
  • R = (3, -3)
4 0
3 years ago
The following spinner has four sections. There are equal sections for 1, 4, and 3. The section for 2 is twice as large as each o
Airida [17]

Answer:

gorge bush doesn't care

Step-by-step explanation:

about black people ~ ye

6 0
2 years ago
What are the solution of the equation 2|×+7|-3=5​
marin [14]

Answer:

x = -3

Step-by-step explanation:

2(x + 7) - 3 = 5     (given)

2x + 14 - 3 = 5     (Distributive Property)

2x + 14 = 8           (Addition Property of Equality)

2x = -6                  (Subtraction Property of Equality)

x = -3                    (Division Property of Equality)

6 0
3 years ago
PLEASE HELP ASAP!!!!
adell [148]


The basic form of the equation is:
4p(x-h) = (y-k)2

(h,k) is the vertex


4(-0.5)(x-1.5) = (y-(-4))2
-2(x-1.5) = (y+4)2
-2(x-1.5) = y2 + 8y + 16
x - 1.5 = (-1/2)(y2 + 8y + 16)
x = (-1/2)y2 - 4y - 8 + 1.5
x = (-1/2)y2 - 4y - 6.5
4 0
3 years ago
Other questions:
  • You need to find the distance across a river, so you make a triangle. BC is 661 feet, m∠B=103.2° and m∠C=14.4°. Find AB.
    8·1 answer
  • I need help with this question
    15·1 answer
  • What is the answer to 1/7÷3
    5·1 answer
  • Twenty-eight soccer teams are playing a tournament. If each team has 19
    15·1 answer
  • Geometry please help
    7·1 answer
  • In Gloria class about 25% of the students wore sweatshirts to school one day. If there are 29 students in her class about how ma
    9·1 answer
  • A professor must randomly select 4 students to participate in a mock debate. There are 15 students in his class. In how many dif
    12·1 answer
  • you had $26 in your pocket. You purchased x pens at $3.50 each. You now have $8.50 in your pocket. write and solve an equation t
    12·1 answer
  • I will fail if i dont pass this test plzz helpp!!​
    5·1 answer
  • Identify the axis of symmetry the function graphed below.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!