Need Help ASAP WILL GIVE BRAINLIEST
1 answer:
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Answer:
Option C is correct.
Step-by-step explanation:
An exponential function is of the form: ....[1] where a is the initial value, x is any real number and b is the growth factor
Also, the b value (growth factor) has been replaced either by (1 + r) or by (1 - r).
Then, the growth "rate" (r) is determined as b = 1 + r.
and the decay "rate" (r) is determined as b = 1 - r
- If b> 1, then it is exponential growth function.
- if 0<b< 1. then it is exponential decay function.
Also, b = 1+ 4
Given the equation:
On comparing given equation with [1] we get;
a = 50 and b = 1.15
Since, b = 1.15 > 1
Therefore, the given equation represents the exponential growth.
(A)
Yes, this equation represents the exponential growth.
(B)
Initial value (a) = 50
(C)
Here growth factor, b = 1.15
and
1+ r = 1.15.
⇒
I believe you meant to write
?
If that's the case I'll solve the one I provided but I'll drop the base 2 to type it faster but you need to put it always!
Remember: log a + log b = log (a*b)
So log (x+2) + log (x-2) = log [(x+2)*(x-2)] = log (x^2 - 4)
Now back to the inequality:
log (x^2 - 4) <span>≤ log 5
Raise both sides as powers of 2 ( Since it's the base of your log)
Now,
x^2 - 4 </span><span>≤ 5
Add 4 both sides:
x^2 </span>≤ 9
Square root both sides
x ≤ +3 or x ≤ -3
Reject the -3 solution as it makes both (x + 2) and (x - 2) negative and a log can never have a negative value inside its brackets.
So x <span>≤ 3 But can never be less than 2 as well for the same previous reason.
Hope that helped.</span>
If that's the case I'll solve the one I provided but I'll drop the base 2 to type it faster but you need to put it always!
Remember: log a + log b = log (a*b)
So log (x+2) + log (x-2) = log [(x+2)*(x-2)] = log (x^2 - 4)
Now back to the inequality:
log (x^2 - 4) <span>≤ log 5
Raise both sides as powers of 2 ( Since it's the base of your log)
Now,
x^2 - 4 </span><span>≤ 5
Add 4 both sides:
x^2 </span>≤ 9
Square root both sides
x ≤ +3 or x ≤ -3
Reject the -3 solution as it makes both (x + 2) and (x - 2) negative and a log can never have a negative value inside its brackets.
So x <span>≤ 3 But can never be less than 2 as well for the same previous reason.
Hope that helped.</span>