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lana66690 [7]
1 year ago
8

What is the standard form for y+2=4/5 (x+4)

Mathematics
1 answer:
yaroslaw [1]1 year ago
4 0

The equation in its standard form is 4x - 5y = -6

<h3>How to determine the standard form of the equation?</h3>

From the question, we have the equation to be

y+2=4/5 (x+4)

Start by multiplying both sides of the equation by 5

So, we have

5(y + 2) =4/5 (x+4) * 5

Evaluate the products

This gives

5y + 10 =4 (x+4)

Next, we open the brackets

So, we have the following representation

5y + 10 =4x + 16

Collect the like terms

4x - 5y = 10 - 16

Evaluate the like terms

This gives

4x - 5y = -6

Hence, the standard form of the equation is 4x - 5y = -6

Read more about linear equations at

brainly.com/question/13738662

#SPJ1

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How many solutions does 1/2 (10x + 15) – 3/2 = 2x + 6 + 3x have
pashok25 [27]

Answer:

1 solutuion

Step-by-step explanation:

write out the equation then distribute everything that's in the parenthesis to 1/2 also combine like term on the other side of the equation. left with 5x+15-3/2=5x+6 . do 15-3/2 u get 13.5. subtract 6 on both sides left with 5x+7.7=5x. subtract 5x on both sides left with x=7.5

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3 years ago
Find the value of m angle 3-m&lt;1
emmainna [20.7K]

Answer:

The value of m\angle 3-m\angle 1 = 50^{\circ}

Step-by-step explanation:

Vertical Angle theorem: It is about the angles that are opposite to each other.

Also, vertical angle are congruent that means vertical angles are equal.

In the given figure; m\angle 3 and 70^{\circ} are vertical angle

then, by vertical angle theorem,  m\angle3 =70^{\circ}.

Supplementary angle: the sum of the angles whose measure on the straight line is 180 degree.

From the figure, 70^{\circ} , \angle 1 and m\angle 2 =90^{\circ} forms a straight line.

then, by the definition of Supplementary angle;

70^{\circ}+m\angle 1 +m\angle 2=180^{\circ}

Substituting the value of  m\angle 2 =90^{\circ} in above equation:

70^{\circ}+m\angle 1 + 90^{\circ} =180^{\circ} or

160^{\circ}+m\angle 1=180^{\circ}

Simplify:

m\angle 1=180^{\circ}-160^{\circ} =20^{\circ}

therefore,  m\angle 1= 20^{\circ} and m\angle 3=70^{\circ},

the value of m\angle3-m\angle1= 70^{\circ}-20^{\circ} =50^{\circ}.






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3 years ago
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