1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zalisa [80]
3 years ago
12

Find peremiter of pqr

Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

79.2 units

Step-by-step explanation:

Tangents to a circle from an external point are congruent , then

PQ = 27.4

QR = 5.9 + 12.2 = 18.1

PR = 12.2 + (27.4 - 5.9 ) = 12.2 + 21.5 = 33.7

Then

perimeter = PQ + QR + PR = 27.4 + 18.1 + 33.7 = 79.2

You might be interested in
What is the perimeter of a triangle with the given side lengths? s1 = x + 4 cm s2 = 3x + 1 cm s3 = 7x + 3 cm P = x + cm
vazorg [7]

Answer:

11x+8  cm = Perimeter

Step-by-step explanation:

A triangle has 3 sides.  We add up all three sides to get the perimeter.

s1+s2+s3 = Perimeter

(x+4) +( 3x+1) + (7x+3) = Perimeter

Combine like terms

11x+8 = Perimeter

4 0
3 years ago
Please simplify the two expressions and tell me how to do number 9 please
alekssr [168]
For the first expression. move the like terms next to each other in the expression.

17c - 5c -3 + 5     Do -3 + 5
17c - 5c + 2          Pretend the c isn't there and do 17 - 5
12c + 2

For the second expression, pretend the b isn't there and do -12 + 10

8b -2b     Now, do 8 - 2
6b

For number 9, you know that since the top of the rectangle is 20cm, the bottom should be too. You can then use the 6cm and 2cm to find out how much of the bottom is missing.

20 - (6 + 2)   Add 6 and 2
20 - 8           Subtract
12

So, the base of the triangle is 12cm. The side of the rectangle tells you that the height of the triangle is 9cm. If you plug those numbers into the triangle area formula, you can find the area of the triangle.

1/2 (b x h)   Plug in the numbers ( b = 12 , h = 9)
1/2 (12 x 9)  Multiply 12 and 9
1/2 (108)      Find half of 180
54

The are of the triangle is 54cm^{2}. Since you need the area of the rectangle minus the are of the triangle, you need the are of the rectangle. That can be found using l x w.

l x w Plug in the values (l = 9 , w = 20)
9 x 20   Multiply
180 

Now, subtract the area of the triangle (54) from the area of the rectangle (180).

180 - 54   Subtract
126

The area of the shaded region is 126cm^{2}.



4 0
3 years ago
Read 2 more answers
Can anyone tell me why this is wrong
Troyanec [42]

Answer:

i, n, e, q, u, a, l, t, y

Step-by-step explanation:

You repeated some letters.

pls give me brainliest and have a nice day! Hope it helps!

3 0
3 years ago
Which angles are coterminal angles for an angle of 125°?
taurus [48]

Answer:

125° = 25/36 π ≈ 0.694 π

Positive coterminal angles: 485°, 845°, 1205°, 1565°

Negative coterminal angles: -235°, -595°, -955°, -1315°

8 0
3 years ago
HELP AGAIN THESE ARE CONFUSING WHEN THEY SAY OF I WILL GIVE BRAINLEST
trasher [3.6K]

Answer:

1 18/35

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • Does anyone know this?
    14·2 answers
  • Find the solution to the system of equations graphed here.
    14·2 answers
  • A train travelled a distance of 6,000km from Lahore to Karachi in 22 hours. And during travel from Karachi to Lahore the train g
    11·1 answer
  • Henry collected data on the favorite type of food of the students of two grades. The table below shows the relative frequencies
    13·2 answers
  • Multiply (2x2 + 3x − 6)(x − 1)
    14·2 answers
  • What is the exact volume of the cylinder
    15·2 answers
  • Which polynomial can be factored as (x-4) (x+2)
    5·1 answer
  • The price of petrol increased from Rs 48 to rs 53.76.
    5·1 answer
  • Mr. Smith’s factory produces 58 brake pads per hour with the current machines. He has decided to invest in new machines that pro
    6·1 answer
  • Triangle ABC has vertices located at A( 0, 2), B (2, 5), and C (−1, 7).
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!