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Nesterboy [21]
3 years ago
12

First consider the system of equations y= -1/2x + 1 and y = x - 5. Then consider the system of inequalities y > -1/2x + 1 and

y < x - 5. When comparing the number of solutions in each of these systems, which statement is true?
A. Both systems have an infinite number of solutions
B. The system of equations has more solutions
C. The system of inequalities has more solutions
D. Both systems have only one solution
Mathematics
2 answers:
adoni [48]3 years ago
7 0

Answer:b

Step-by-step explanation:

viktelen [127]3 years ago
4 0

Answer:

the answer is C, NOT B

Step-by-step explanation:

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What are the solutions to the equation -54 + 6x = 0
Sladkaya [172]

Answer:

x=9

Step-by-step explanation:

  1. -54 + 6x  =   6 • (x - 9)
  2. Solve :    6   =  0
  3.  Solve  :    x-9 = 0
  4. Add  9  to both sides of the equation :     x = 9
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Use the distributive property to rewrite the following expression.
Gekata [30.6K]
Answer: 2n-8

Explanation: 2(n-6)+4 you bring 2 into the parentheses so 2 x n is just 2n
then 2 x -6 = -12
New equation 2n-12 +4
Now you combine-12 and 4 which is -8
Finale equation: 2n-8
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3 years ago
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A caterer made 4 grilled cheese sandwiches, 7 ham sandwiches, and 6 turkey sandwiches. How many sandwiches did the caterer make
Dmitriy789 [7]
17. Because 7 plus 4 equals 11 and if you add 6 you get 17
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What are the quotient and remainder of (x^5-x^3+-5) divided by (x-2)
pishuonlain [190]

Answer:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

Step-by-step explanation:

You can do this through synthetic division. It is a shorthand way of dividing polynomials.

First you need to make your divisor equal to zero so you can solve for what goes into the division box:

x - 2 = 0 →     x = 2

The next step is to arrange your polynomials in descending powers. All missing terms, you will put in a zero.

x⁵ - x³ + (-5)   →  x⁵ + 0x⁴- x³ + 0x² + 0x + (-5)

Now you can proceed to synthetic division. Make an upside down division box with the divisor outside and the coefficients of the dividend listed, along with their sign. Leave a space below the divident

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

Next you bring down the first coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

        +1    

Then you multiply it by the divisor and write the product under the next coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>           +2                                   </u>

        +1    

Next add the column and put the sum below it:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2                                   </u>

        +1    +2

Then multiply again and repeat until you reach the last coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2    +4   +6   +12   +24 </u>

        +1    +2    +3   +6   +12    +19

Now that you have your results, add  in the x and their powers. The powers will start with the highest power but 1 less than the dividend. Since the dividend's highest power is 5, then the quotient's highest power will be 4. Then write it in descending order :

+1x⁴    +2x³    +3x²   +6x   +12   +19

Now the last coefficient is your remainder. So your results will be:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

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When you distribute and combine like terms, the result is x^3-27

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