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Nesterboy [21]
3 years ago
12

First consider the system of equations y= -1/2x + 1 and y = x - 5. Then consider the system of inequalities y > -1/2x + 1 and

y < x - 5. When comparing the number of solutions in each of these systems, which statement is true?
A. Both systems have an infinite number of solutions
B. The system of equations has more solutions
C. The system of inequalities has more solutions
D. Both systems have only one solution
Mathematics
2 answers:
adoni [48]3 years ago
7 0

Answer:b

Step-by-step explanation:

viktelen [127]3 years ago
4 0

Answer:

the answer is C, NOT B

Step-by-step explanation:

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Determine the discriminant for the given equation x^2+4x+5=0. Then describe the roots(how many and what type).
Fed [463]

Discriminant = b^2 - 4ac, where a, b and c come from the form of the quadratic equation as ax^2 + bx + c

Discriminant = (4)^2 - 4(1)(5)
= 16 - 20
= -4

-4 < 0, therefor there are no roots

(If the discriminant = 0, then there is one root
If the discriminant > 0, there are two roots, and if it is a perfect square (eg. 4, 9, 16, etc.) then there are two rational roots
If the discriminant < 0, there are no roots)
3 0
3 years ago
Answer Choices
sasho [114]

Answer:

c) only Anne

Step-by-step explanation:

I just did the test. Hope this helps! : )

4 0
2 years ago
Write an inequality for the graph.
ivann1987 [24]

Use y = mx + b to determine the equation of the graph, then decided the inequality symbol.

m = +5/+6 = \frac{5}{6}    b = 5

y =  \frac{5}{6}x + 5

6y = 5x + 30

-30 = 5x - 6y   ⇒   5x - 6y = -30

Now let's look at the inequality symbol:  The shaded area is below so it will be a less than symbol and it is a solid line so the equal sign is included.

Answer: 5x - 6y ≤ -30



7 0
3 years ago
Read 2 more answers
Plane X contains point C. Plane Y contains points A and
mr Goodwill [35]

Answer:

so can't see the graph

Step-by-step explanation:

but if you can give a picture of the graph i could help out.

8 0
3 years ago
Read 2 more answers
What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x
lora16 [44]
\frac{x^2-16}{x^2+5x+6} / \frac{x^2+5x+4}{x^2-2x-8}

We can begin by rearranging this into multiplication:

\frac{x^2-16}{x^2+5x+6} * \frac{x^2-2x-8}{x^2+5x+4}

Now we can factor the numerators and denominators:

\frac{(x+4)(x-4)}{(x+3)(x+2)} * \frac{(x-4)(x+2)}{(x+4)(x+1)}

The factors (x+4) and (x+2) cancel out, leaving us with:

\frac{(x-4)}{(x+3)} * \frac{(x-4)}{(x+1)}

Our answer comes out to be:

\frac{(x-4)^{2} }{(x+3)(x+1)} or \frac{ x^{2} -8x+16}{ x^{2}+4x+3 }

Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4
4 0
3 years ago
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