Cosine = adjacent / hypotenuse
cos (49)= x/27
27 * cos(49) = x
27 * 0.656 = x
x = 17.7
Answer:
Step-by-step explanation:
Not entirely sure about the first one, but I'll try the others:
2- log base 8 (8x) = log base 8 (8) + log base 8 (x) = 1 + log base 8 (x)
3 - log base 3 (5^x) = x log base 3 (5)
4 - log base 2 (5/x) = log base 2 (5) - log base 2 (x) = In 5 - In x
5 - log base 2 (2^x) = x log base 2 (2) = x · 1 = x
Answer:60%
Step-by-step explanation:
Answer:
Step-by-step explanation:
![\sf 3x+12 = 36\\\\Subtracting \ 12 \ to \ both \ sides\\\\3x=36-12\\\\3x = 24\\\\Dividing \ both \ sides \ by \ 3\\\\x = 24/3\\\\x = 8\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%203x%2B12%20%3D%2036%5C%5C%5C%5CSubtracting%20%5C%2012%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C3x%3D36-12%5C%5C%5C%5C3x%20%3D%2024%5C%5C%5C%5CDividing%20%5C%20both%20%5C%20sides%20%5C%20by%20%5C%203%5C%5C%5C%5Cx%20%3D%2024%2F3%5C%5C%5C%5Cx%20%3D%208%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
<em>His son is 10 years old.</em>
Step-by-step explanation:
Now Aaron's son is s years old, and Aaron is 3s years old.
In 10 years, Aaron's son will be s + 10 years old, and Aaron will be 3s + 10 years old.
In 10 years, Aaron's age will be twice the son's age.
3s + 10 = 2(s + 10)
3s + 10 = 2s + 20
s = 10
His son is 10 years old.
