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trasher [3.6K]
3 years ago
13

Plz help me It’s due by tonight

Mathematics
2 answers:
Olegator [25]3 years ago
7 0

so this is the solution to the problem.

Money that Keith has  at the beginning of the summer = $ 500 )

Money that keith  wants to have at the end of the summer = At least $200

Money that Keith withdraws every week =$25

Let w to represent the number of weeks in the summer

In consequence , the correct inequality should be:

Amount at the beginning of the summer- money withdrawn every week ≥ money at the end of the summer

Replacing with the values we know:

500-25w≥200. The correct answer is A.

PLEASE MARK ME BRAINLIEST

natulia [17]3 years ago
5 0

Answer:s

12 weeks

Step-by-step explanation:

if keith starts with $500 and wants to end with (at least) $200

he can withdrawn up to $500-$200=$300

if he withdraws $25 week the $300 will last $300 $25 week =12 weeks

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I need help pleaseee
kumpel [21]

Answer: $7448

Step-by-step explanation:

Year 1: 1.218x

Year 2: 1.218(1.218x)

Year 3: 1.218(1.218(1.218x))

Year 4: 1.218(1.218(1.218(1.218x)))

Year 5: 1.218(1.218(1.218(1.218(1.218x))))

Year 6: 1.218(1.218(1.218(1.218(1.218(1.218x)))))

Year 7: 1.218(1.218(1.218(1.218(1.218(1.218(1.218x))))))

Year 8: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x)))))))

Year 9: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x))))))))

Year 10: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x)))))))))

Year 11: x(1.218¹¹)

Year 12: x(1.218¹²) = 79,400

         

x(10.6602517) = 79,400

x = 79,400/10.6602517

x=7448.22939

x = $7448

Hope this helps!

6 0
2 years ago
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Marizza181 [45]

Answer:

The step which is not necessary is,

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Step-by-step explanation:

The step which is not necessary when solving this system of equations by graphing is,

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3 years ago
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