the length of a rectangle is 2 in more than it's w i d t h the area of a rectangle is equal to 1 inch less than three times a pe
rimeter find the length and width of the rectangle
1 answer:
If we let x and y represent length and width, respectively, then we can write equations according to the problem statement.
.. x = y +2
.. xy = 3(2(x +y)) -1
This can be solved a variety of ways. I find a graphing calculator provides an easy solution: (x, y) = (13, 11).
The length of the rectangle is 13 inches.
The width of the rectangle is 11 inches.
______
Just so you're aware, the problem statement is nonsensical. You cannot compare perimeter (inches) to area (square inches). You can compare their numerical values, but the units are different, so there is no direct comparison.
.. x = y +2
.. xy = 3(2(x +y)) -1
This can be solved a variety of ways. I find a graphing calculator provides an easy solution: (x, y) = (13, 11).
The length of the rectangle is 13 inches.
The width of the rectangle is 11 inches.
______
Just so you're aware, the problem statement is nonsensical. You cannot compare perimeter (inches) to area (square inches). You can compare their numerical values, but the units are different, so there is no direct comparison.
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Answer:
here's the answer to your question
Given:
The length of field is n yards.
The length of a field in feet is a function f(n).
To find:
The function rule for this situation.
Solution:
We know that,
1 yard = 3 feet
Using this conversion, we get
n yard = 3n feet
The length of field is n yards. So, the length of the field is 3n feets.
The length of a field in feet is a function f(n). So,
Therefore, the required function rule for this situation is .