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2 years ago

HELP PLEASE!!!! THERE R 3 QUESTIONS. MAKE SURE TO ANSWER ALL 3!!! TYSM

Mathematics

2 answers:

sergeinik [125]2 years ago

6 0

Answer:
1. k=2
2. b=2f
3. 68

Explanation

1. y=kx (replace x&y with 2 values)

12=k(6) (isolate k)
/6 /6

2=k *check with another value to see if k truly is 2

2. since the constant of variation is 2, we can see that 2x the number of flowers make up the birds. so...

b(birds/y-value)=2(constant)f(number of flowers)

b=2f

3. input 34 into f, since there are 34 flowers

b=2*34 (use mental math)

b=68
in other words, there will be 68 birds.

andrew11 [14]2 years ago

4 0

A1- K=2
A2- b=2f
A3- 68

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2 years ago

-a^2+46a-480=0<br> a - ?

sattari [20]

a = 30
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-a² + 46a -480 = 0

(-a + 30) (a -16) = 0
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mezya [45]

Let's put more details in the figure to better understand the problem:

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$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

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$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

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