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3 years ago

How do you solve this ?

Mathematics

2 answers:

Anton [14]3 years ago

6 0

Answer:

x = 37 mm

Step-by-step explanation:

using the Pythagorean theorem:

m² = 13² - 5² = 169 - 25 = 144

m = √144 = 12 mm

x² = 12² + 35² = 144 + 1225 = 1369

x = √1369 = 37 mm

labwork [276]3 years ago

6 0

Answer:

x=37.3

Step-by-step explanation:

Since we're looking for "x" we need to use "the Pythagorean theorem".

13mm will be our "A" and 35mm will be our "B" will "x" being the hypotenuse.

Since x is the hypotenuse, it needs to be a number greater than 13 and 35.

c=√(a² + b²)

Making it c=√(13² + 35²)

Making C=37.336 or 37.3

Therefore making, x=37.3

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A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

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3 years ago

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Shalnov [3]

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timama [110]

Answer:

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Step-by-step explanation:

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irina [24]

Answer:

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4 years ago

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Step-by-step explanation:

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