C because the moon has less mass than Earth the Gravitational Force is less and thus anything on the moon weighs less than on Earth
Answer the Air Pollution From a Power Plant photograph. Tell students that pollutants emitted into the atmosphere do not stay in the atmosphere or even directly above the polluting source forever. They move throughout the atmosphere and are moved and removed by natural processes.
Explanation:
Carbon ,hydrogen ,and oxygen
Answer:
Upon nutrient limitation, budding yeast will produce daughter cells less than 20% of the mother cell size. This asymmetric division may select for growth functions that are efficient over a larger range in cell sizes, such as exponential growth. In turn, efficient growth over a large size range lessens the pressure to have precise size control.
Explanation:
In wild-type cells growing in nitrogen-rich medium, the size threshold to enter mitosis is high, and the G1/S size control is cryptic because cell division produces daughter cells with a size greater than the minimum required to initiate S phase. In these conditions, G2 is long and G1 is short. However, the cell size threshold to enter mitosis is greatly reduced when wild-type cells are shifted to medium with a poor nitrogen source, such as minimal medium with proline, isoleucine, or phenylalanine. In these conditions, wild-type cells initiate mitosis at a reduced cell size, generating two daughter cells that are smaller than the critical size threshold required to progress through G1/S
The term 2pq represented in the hardy-weinberg equation is the frequency of heterozygotes and is denoted as option D.
<h3>What is Hardy-weinberg equation?</h3>
This mathematical equation is used to calculate the genetic variation of a population at equilibrium and can be seen below:
p² + 2pq + q² = 1
where
p² is dominant homozygous frequency (AA)
2pq is heterozygous frequency (Aa)
q² is recessive homozygous frequency (aa).
The 2pq can be seen as the heterozygous frequency which is therefore the reason why option D which is frequency of heterozygotes was chosen as the most appropriate choice.
Read more about Hardy-weinberg equation here brainly.com/question/5028378
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