Answer: -1 < x < 8
x = 3
x ≠ 2
<u>Step-by-step explanation:</u>
Isolate x in the middle. Perform operations to all 3 sides.
-6 < 2x - 4 < 12
<u>+4 </u> <u> +4</u> <u>+4 </u>
-2 < 2x < 16
<u>÷2 </u> <u>÷2 </u> <u> ÷2 </u>
-1 < x < 8
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Isolate x. Solve each inequality separately. Remember to flip the sign when dividing by a negative.
4x ≤ 12 and -7x ≤ 21
<u>÷4 </u> <u>÷4 </u> <u> ÷-7 </u> <u>÷-7 </u>
x ≤ 3 and x ≥ 3
Since it is an "and" statement, x is the intersection of both inequalities.
When is x ≤ 3 and ≥ 3? <em>when x = 3</em>
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Isolate x. Solve each inequality separately.
15x > 30 or 18x < -36
<u>÷15 </u> <u> ÷15 </u> <u> ÷18 </u> <u>÷18 </u>
x > 2 or x < 2
Since it is an "or" statement, x is the union of both inequalities.
When we combine the inequalities, x is every value except 2.
x ≠ 2
Answer:
x = 2 sqrt(2) - 2 or x = -2 - 2 sqrt(2)
Step-by-step explanation:
Solve for x:
x^2 + 4 x = 4
Add 4 to both sides:
x^2 + 4 x + 4 = 8
Write the left hand side as a square:
(x + 2)^2 = 8
Take the square root of both sides:
x + 2 = 2 sqrt(2) or x + 2 = -2 sqrt(2)
Subtract 2 from both sides:
x = 2 sqrt(2) - 2 or x + 2 = -2 sqrt(2)
Subtract 2 from both sides:
Answer: x = 2 sqrt(2) - 2 or x = -2 - 2 sqrt(2)
<span>when the altitude is </span>drawn from the vertex of the right angle<span> of a right triangle to its hypotenuse, the altitude equals the product</span> of the two segments of the hypotenuse<span>.
(w+9)</span>²=8*18=144
w+9=12 or w+9=-12
w=3 (discard the negative number)
use the same method, z=√(9*11)=3√11
next, you can use the Pythagorean theorem to find x and y.
x=√(9²+99)=√180=6√5
y=√(11²+99)=√220=2√55
Answer:
1, x=1 , 1=z , x
Step-by-step explanation:
