15x^3+4x^2+14x+12
Multiply 3x by every value in the second bracket. Then multiply 2 by every value in the second bracket. Add like terms. (Only answers with the same square are like terms.)
<h3>
Answer:</h3><h3>D</h3><h3 /><h3>
Step-by-step explanation:</h3><h3>
</h3><h3>In a function, an input (x) value should have only one output (y) value.</h3><h3 />
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<em>Example: (View attached image below). </em><em>Table A</em><em> is a function because each </em><em>x </em><em>value has only 1 </em><em>y</em><em> value. But </em><em>Table B</em><em> is not a function because the </em><em>x value</em><em> of </em><em>4 </em><em>has </em><em>2 y values</em><em>.</em>
Step-by-step explanation:
By Law of Indices, a^m / a^n = a^(m-n).
Therefore a² / a⁸ = a^(-6).
x = -6.
Answer:
Step-by-step explanation:
hello :
p²+30p = p(p+30)
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
