<em>The</em><em> </em><em>clock</em><em> </em><em>says</em><em> </em><em>4</em><em>:</em><em>3</em><em>o</em><em> </em><em>am</em><em>/</em><em>pm</em><em> </em><em>as</em><em> </em><em>big</em><em> </em><em>one</em><em> </em><em>is</em><em> </em><em>at</em><em> </em><em> </em><em>6</em><em> </em><em>and</em><em> </em><em>small</em><em> </em><em>near</em><em> </em><em>4</em>
Answer:
r = √13
Step-by-step explanation:
Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms: x^2 + 6x + y^2 -2y = 3. Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."
We need to "complete the square" of x^2 + 6x. I'll just jump in and do it: Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x: x^2 + 6x + 3^2 - 3^2. Then do the same for y^2 - 2y: y^2 - 2y + 1^2 - 1^2.
Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2. Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1. Making these replacements:
(x + 3)^2 - 9 + (y - 1)^2 -1 = 3. Move the constants -9 and -1 to the other side of the equation: (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13
Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r: r^2 = 13, so that the radius is r = √13.
Answer:428 7/100
Step-by-step explanation:
Answer:
the answer would be 928
Step-by-step explanation:
you have 232 kit kats and if you put all of them in fourths you would multiply them by 4. 232 x 4= 928
Answer:
The answer is 11.7
Step-by-step explanation:
hope it will help you
