Answer:
1) A
2) min; min; max; max
3) y = x² + 5x - 3
Step-by-step explanation:
f(x) = x² + 2(x)(5) + 5² - 5² + 24
f(x) = (x + 5)² - 25 + 24
f(x) = (x + 5)² - 1
In ax² + bx + c,
if a > 0, it's a min
if a < 0, it's a max
y = ax² + bx + c
Using (0,-3)
-3 = a(0)² + b(0) + c
c = -3
y = ax² + bx - 3
Using (1,3)
3 = a + b - 3
a + b = 6
Using (-1,-7)
-7 = a(-1)² + b(-1) - 3
-7 + 3 = a - b
a - b = -4
b = a + 4
a + (a + 4) = 6
2a = 2
a = 1
b = 5
y = x² + 5x - 3
Answer:
non linear
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!
tinyurl.com/wpazsebu
Answer:the cost of one day lily = $9 and cost of one pot of ivy = $2
Step-by-step explanation:
Step 1
let day lilies be rep as d
and ivy be represented as i
So that The expression for what Willie spent on 12 day lilies and 4 pots of ivy = $116 be
12 d+ 4i = 116 ---- equation 1
and for Anjali spending $60 on 6 day lilies and 3 pots of ivy be
6d+ 3i = $60------ equation 2
Step 2 --- Solving
12 d+ 4i = 116 ---- equation 1
6d+ 3i = $60------ equation 2
Multiply equation 2 by (2) and subtracting equation 1 from it
12d+ 6i= 120
--12 d+ 4i = 116
2 i= 4
i = 4/2 = 2
TO find d, putting the value of i = 2 in equation 1 and solving
12d+ 4(2) = 116
12d= 116-8
12d= 108
d= 108/12= 9
Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2
