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Firlakuza [10]
3 years ago
5

Find the missing value.

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Step-by-step explanation:

1.(4,16) and (x,24)

4/16 = x/24

Now you will cross multiple to get a liner equation.

16x= 4×24

Now you will divide both sides by the coefficient of x which is 16.

16x/16=4×24/16

Now 16 will cancel 16 and the equation will be like this

x=4×24/16

Now 4 will cancel 16 to get 4 and the 4 at the the nominator will cancel 24 to get 6.

Therefore x = 6.

2.(3, 4) and (9, y)

3/4 = 9/y

cross multiple to get a linear equation.

3y = 4×9

Divide both sides by the coefficient of y.

3y/3=4×9/3

As a said before 3 will cancel 3 to make y stand alone.

y = 36/3

y = 12.

3.(3,18) and (x,30)

3/18 = x/30

18x = 3x30

18x/18 = 3×30/18

x = 5

Therefore x = 5.

4.(3,36) and (6,y)

3/36 = 6/y

3y = 6×36

3y/3 = 6×36/3

y = 216/3

y = 72

Therefore y = 72.

5.(3,39) and (x,65)

3/39 = ×/65

39x = 3× 65

39x/39 = 3×65/39

x = 5

Therefore x = 5.

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Find the sum of the series and show your process for finding each term leading to the final sum.
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ANSWER

\sum_{k=3}^5( - 2k + 5) =  - 9

EXPLANATION

The given series is

\sum_{k=3}^5( - 2k + 5)

This series is finite.

The expanded form is

\sum_{k=3}^5( - 2k + 5) = ( - 2 \times 3 + 5) + ( - 2 \times 4 + 5) + ( - 2 \times 5 + 5)

This simplifies to

\sum_{k=3}^5( - 2k + 5) = ( - 6 + 5) + ( - 8+ 5) + ( - 10+ 5)

\sum_{k=3}^5( - 2k + 5) = ( - 1) + ( - 3) + ( - 5)

\sum_{k=3}^5( - 2k + 5) =  - 9

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Answer:

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Step-by-step explanation:

Use the formula C= πd, where C is circumference, π is pi, and d is diameter.

Input the numbers and we'll shorten π to 3.15

C=3.15(15)

C≈47.25

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2 years ago
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