Let's have Steve's age be <em>x</em><em />, and his father's age be <em>f</em>
Then, we can set up equations
Steve is one-fourth as old as his father goes to an equation as x=(1/4)f
In five years (x+5), Steve will be one-third as old as his father will be (f+5). This goes to an equation as x+5=(1/3)(f+5)
We can then solve the first equation for either variable (I will be doing f), and plug it in for a system of equations.
x=(1/4)f
4x=f ← plug that in for f in the next equation
x+5 = (1/3)(4x+5) ← Solve this for x
3(x+5)=4x+5
3x+15=4x+5
3x+10=4x
10=1x
x=10
Therefore, Steve's age is 10. His father's age is <em>f=4x, </em>plug in 10 for x, and his father's age is 40
Answer:
789_278913_97/1_397/_317074
Step-by-step explanation:
gvyhfeuoyefbhbhioevfbebo no ohef. ve h hoierv wfv hirev ihoev si o w our w h. while vhio f hio
28^2=784
29^2=841
784<830<841
therefore sqrt784<sqrt830<sqrt841
therefore 28<sqrt830<29
Done!
