What is the equation of the line that passes through the point (-3,2) and has a slope of -3
1 answer:
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Answer:
Step-by-step explanation:
32
Step 1 : Draw PQ = 6cm
Step 2 : Construct 60 degree at Q. [Given PQR = 60=> Q = 60 ]
Step 3 : Take 5 cm on compass and mark 5cm on the 60 degree
line constructed at Q.
Step 4 : The arc of 5cm and 60 degree line meets is the point R.
[Given QR = 5cm ]
Step 5 : Given PQ || SR so construct a 120° at R ,
because ∠PQR and ∠QRS are supplementary angle.
[ ∠PQR + ∠QRS = 60 + 120 = 180° ]
Step 6 : At P , take 6.5 cm on compass and mark on the line drawn in
Step 5, to get S. [ Given PS = 6.5 ]
33
Given adjacent sides : 4.8 and 4.2
And it is a rectangle.
Step 1 : construct AB = 4.8 cm
Step 2 :At A and B construct 90 degree
Step 3: On the compass take 4.2cm and mark on the 90degree lines
from A and B.
Step 4 : Mark that as C and D respectively.
Step 5 : Join CD
