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omeli [17]
3 years ago
8

Solve the inequality: 1/3x + 8 _< 11

Mathematics
2 answers:
liraira [26]3 years ago
8 0
Answer: 21

Step by step explanation:
serg [7]3 years ago
4 0

Answer:x=-21

Step-by-step explanation:

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Given that ABCD~JKLM <br> find the ratio of the perimeter of ABCD to JKLM
Westkost [7]

Answer:

The ratio of the perimeter of ABCD to JKLM is;

b. 3/5

Step-by-step explanation:

Given that ABCD ~ JKLM, where;

DC and ML are corresponding sides

AD and JM are corresponding sides

AB and JK are corresponding sides

Therefore;

DC/ML = AD/JM = AB/JK

Plugging in the values of the variables gives;

9/15 = z/10 = x/12

∴ z = 10×9/15 = 6

x = 12×9/15 = 7.2

9/15 = 6/y

y = 6 ×15/9 = 10

The perimeter of the quadrilateral ABCD = AB + BC + DC + AD

∴ The perimeter of the quadrilateral ABCD = 6 + 6 + 9 + 7.2 = 28.2

The perimeter of the quadrilateral JKLM = JK + JM + ML + LK

∴ The perimeter of the quadrilateral JKLM = 12 + 10 + 15 + 10 = 47

The ratio of the perimeter of ABCD to JKLM = 28.2/47 =0.6 = 3/5.

4 0
3 years ago
EASY MATH QUESTION Urgent pls​
Serga [27]

Answer:

I don't know that is hard

Step-by-step explanation:

You said this was an easy math question.

8 0
3 years ago
Complete the equation of variation where y varies inversely as x and y = 0.125 when x = 8.
patriot [66]
Complete the equation of variation where y varies inversely as x and y = 0.125
when x=8

3 0
3 years ago
scrie patru perechi de numere naturale astfel incat diferenta numerelor din fiecare pereche sa fie 2989
ioda
Do you happen to have this in english i dont understand it at all :/
7 0
4 years ago
A customer wants you to enlarge a photo to 22 its current height. The photo's current height is 31 inches. What should its enlar
stiks02 [169]

Answer:

The enlarged height of the photo must be 682 inches

Step-by-step explanation:

A customer wants to enlarge the image by 22 times

Hence, the scale factor = +22

Now, the current height of the photo = 31 inches

Therefore, to find the enlarged height : we need to multiply the scale factor of the required image by the current height of the photo.

Hence, Enlarged Height = 22 × 31

                                         = 682 inches

So, The enlarged height of the photo must be 682 inches

8 0
3 years ago
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