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Which sequence can be generated from the formula f(x + 1) = (f(x))? x, 2x, 4x, 8x, … x, 2x, 4x, 6x, …

Contact [7]

The mathematical formula f(x + 1) = (f(x)) is like an arithmetic progression where the original value is f(x), an = f(x+1) , and d is equal to 1. In thsi case, if a0 is equal to x, then the progression should become x+1, x+2, x+3 and so on until x+n. There is no multiplication involved only addition process/

4 0

3 years ago

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Determine the area under the standard normal curve that lies to the left of (a) upper z equals 0.02 comma (b) upper z equals n

Anuta_ua [19.1K]

A) 0.50798
b) 0.42465
c) 0.35197
d) 0.040930

3 0

3 years ago

68% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all, how many child tickets did it se

Mnenie [13.5K]

Answer:

$\boxed{\bf\: The \: park \: sold \boxed{ 34{}} \: child \: tickets.}$

Step-by-step explanation:

Given:

Percentage of Tickets sold at a water park - 68%

The Number of Tickets if the park sold in all - 50

To Find:

The Number of child tickets the park sold.

Solution:

We know that 68% equals to 68/100.

Step 1: Multiply 68/100 by 50 which is the number of tickets the park sold :-

$\sf \: = \: \cfrac{68}{100} \times 50$

Note:The Simplified form of 68/100 * 50 would be the answer to this question.

Step 2: Cancel One zero of 50 and one zero of 100,That is:-

$\sf = \cfrac{68}{ 10\cancel0} \times 5 \cancel0$

Results to,

$\sf = \cfrac{68}{10} \times 5$

Step 3: Cancel 5 and 10, That is:-

$\sf = \cfrac{68}{ \cancel{10 }} \times \cancel5$

Results to,

$\sf =\: \cfrac{68}{2} \times 1$

$\sf = \cfrac{68}{2}$

Step 4: Cancel 68 and 2, That is:-

$\sf =\: \cfrac{ \cancel{68}}{ \cancel2}$

Results to,

$\sf = \cfrac{34}{1}$

$\sf = 34$

34 is the result.

Hence,

$\underline{ \rm \: The \: park \: sold \: \bold{ 34 } \: child \: tickets.}$

________________________________

I hope this helps!

Let me know if you have any questions.I am joyous to help!

6 0

3 years ago

A police officer would like to estimate the proportion of petty theft cases that have gone unsolved in a large city. He takes a

nata0808 [166]

Answer:

$0.625 \pm 1.645*0.0571$

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

$\pi$ is the estimate

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ , also called the critical value.

The standard error is:

$s = \sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level critical value

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.955$ , so $z = 1.645$ .

Estimate:

72 petty theft cases and finds 45 of these have gone unsolved.

So $\pi = \frac{45}{72} = 0.625$

Standard error:

$s = \sqrt{\frac{\pi(1-\pi)}{n}} = \sqrt{\frac{0.625*0.375}{72}} = 0.0571$

Answer:

$0.625 \pm 1.645*0.0571$

7 0

3 years ago

A greeting card company can produce a box of cards for $7.50. If the initial investment by the company was $50,000, how many box

larisa86 [58]

Answer:

If cost of one box of card is $7.50 then the no of cards produced is 6667 cards and if cost of one box of card is $10.50 then the no of cards produced is 4762 cards

Step-by-step explanation:

The cost of one box of cards = $7.50

Initial investment = $50,000

No of box of cards produced = Initial investment / cost of one box of card

No of box of cards produced = 50,000/7.50

No of box of cards produced = 6667 cards.

if the cost of one box of cards is increased = $10.50

No of box of cards produced = Initial investment / cost of one box of card

No of box of cards produced = 50,000/10.50

No of box of cards produced = 4762 cards.

So, if cost of one box of card is $7.50 then the no of cards produced is 6667 cards and if cost of one box of card is $10.50 then the no of cards produced is 4762 cards

5 0

3 years ago

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