Please answer this question

How do I prove that (1+sinx)/cosx=cos(-x)/(1+sine(-x))

stira [4]

$\dfrac{1+\sin x}{\cos x}=\dfrac{\cos (-x)}{1+\sin(-x)}\\
\dfrac{1+\sin x}{\cos x}=\dfrac{\cos x}{1-\sin x}\\
\cos^2 x=(1+\sin x)(1-\sin x)\\
\cos^2 x=1-\sin^2 x\\
\sin^2 x+\cos^2 x=1
$

5 0

3 years ago

Which is the better deal? Question 2 options: 1 lb of apples for $2.50 3 lbs of apples for $4.25 5 lbs of apples for $7.20 10 lb

dem82 [27]

3 lbs of apples for 4.25

4 0

3 years ago

The following table shows how the average constituency changes for two regional governing boards, joshua and salinas, when a new

AVprozaik [17]

The relative unfairness of an apportionment that gives a new board member to joshua rather than to salinas will be

<h3>How to calculate the values?</h3>

The relative unfairness of an apportionment that gives a new board member to joshua rather than to salinas will be:

= (1520 - 1232)/1232

= 288/1232

= 0.234

The relative unfairness of an apportionment that gives a new board member to salinas rather than to Joshua will be:

= (1448 - 1333)/1333

= 115/1333

= 0.086

The regional governing board that should receive the new board member is Salinas.

Learn more about tables on:

brainly.com/question/3632175

#SPJ1

5 0

1 year ago

If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num

weeeeeb [17]

Answer:

Step-by-step explanation:

$x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right$

$\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right$

$\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}$

7 0

2 years ago

Evaluate the following expression. 8to the power of 3 − 9 ⋅ 2 ÷ 3 = ?

ahrayia [7]

Answer:

8^-3 I think (i'm too lazy to simplify)

Step-by-step explanation:

3 - 9 * 2 ÷ 3 = ?

3 - 18 ÷ 3 = ?

3 - 6 = -3

8 to the power of -3

hmmmm i dont think im right tell me if im not

3 0

2 years ago

Please answer this question ​

Please answer this question