We will get the number of possible selections, and then subtract the number less than 25 cents.
We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.
That's 5*4*3 = 60 selections
Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels.
To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2 on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).
If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.
And there is 1 other selection less than 25 cents, 2 dimes and no nickels.
So that's 4+3+1 = 8 selections which we must subtract from the 60.
Answer 60-8 = 52 selections of coins worth 25 cents or more.
Answer:
6:3:8
Step-by-step explanation:
We need to find the amount of:
Frogs= Joes has 6
Snakes= Joe has 3
Hamster= Joe has 8
So, the ratio of Joe's frogs and snakes to hamsters is 6: 8 : 3.
Hope that helped! :)
0.06 or you can just put 6.
Basically, you have to multiply 30% x 20.
Glad I could help☺️
Answer:
0.02.90 and 2.90
Step-by-step explanation:
2% of 90 equal to both 0.02.90 because are worth same.
Answer:
=760
Step-by-step explanation:
Area: ![\pi r^{2}](https://tex.z-dn.net/?f=%5Cpi%20%20r%5E%7B2%7D)
diameter= 44
radios= 22
area of full circle:
3.14(22)^2
= 1519.76
Area of half circle"
1519.76/2= 759.88
=760