Answer:
38 cents
Step-by-step explanation:
quarter= 25
nickles= 5
pennies= 1
5+5+25+3= 38
When ever you have percentages, it should be helpful to bear in mind you can express them as multipliers. In this case, it will be helpful.
So, if we let:
a = test score
b = target score
then, using the information given:
a = 1.1b + 1
a = 1.15b - 3
and we get simultaneous equations.
'1.1' and '1.15' are the multipliers that I got using the percentages. Multiplying a value by 1.1 is the equivalent of increasing the value by 10%. If you multiplied it by 0.1 (which is the same as dividing by 10), you would get just 10% of the value.
Back to the simultaneous equations, we can just solve them now:
There are a number of ways to do this but I will use my preferred method:
Rearrange to express in terms of b:
a = 1.1b + 1
then b = (a - 1)/1.1
a = 1.15b - 3
then b = (a + 3)/1.15
Since they are both equal to b, they are of the same value so we can set them equal to each other and solve for a:
(a - 1)/1.1 = (a + 3)/1.15
1.15 * (a - 1) = 1.1 * (a + 3)
1.15a - 1.15 = 1.1a + 3.3
0.05a = 4.45
a = 89
Answer:
F. 6 x 22
Step-by-step explanation:
- 6 has more than two factors ( 1, 6, 2, 3), which makes it a composite number.
- 22 has more than two factors (1, 22, 2, 11), which makes it a composite number.
- Therefore, F is the correct answer.
Answer:
Mean=50
Step-by-step explanation:
The mean of a probability distribution is a <u>measure of central tendency</u>,and gives information about how the possible values of x are distributed.
The vertical axis measures the probability of finding a specific value of x in the sample. The probability of finding a value near the mean is high (that is why the value of the function that is depicted in the vertical axis, increases as we get closer to the mean=50): this is because the mean is that value of x around which higher probability of occurrence is associated.
When
, you're left with
When
or
, you're left with
Adding the two equations together gives
, or
. Subtracting them gives
,
.
Now, you have
By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that
and
. These alone tell you that you must have
and
.
So the partial fraction decomposition is