Solve. W=2, p=3 ........ 5p-2w
2 answers:
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Answer:
A quadratic equation can be written as:
a*x^2 + b*x + c = 0.
where a, b and c are real numbers.
The solutions of this equation can be found by the equation:
Where the determinant is D = b^2 - 4*a*c.
Now, if D>0
we have the square root of a positive number, which will be equal to a real number.
√D = R
then the solutions are:
Where each sign of R is a different solution for the equation.
If D< 0, we have the square root of a negative number, then we have a complex component:
√D = i*R
We have two complex solutions.
If D = 0
√0 = 0
then:
We have only one real solution (or two equal solutions, depending on how you see it)
Answer:
108cm (B)
Step-by-step explanation:
Find the area of the triangle first.
6 * 4 = 24/2 = 12
Multiply by the width.
12 * 9 = 108
Step-by-step explanation:
1.
Therefore,
2.
Use the identity
We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:
3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,
Solving for tan x: