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2 years ago

Help me quick!!!!!

Mathematics

1 answer:

PolarNik [594]2 years ago

3 0

Answer:

I don't know thank answer sorry I just really need points you can report me if you want but I REALLY need some

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Kyles net worth is 500

iren [92.7K]

What is the question?

8 0

3 years ago

Read 2 more answers

Determine the intercepts of the line.<br> y-6= 4( + 5)<br> y-intercept:<br> z-intercept

Shtirlitz [24]

Answer:

(0, 26)
(-6.5, 0)

Step-by-step explanation:

Turn the equation into slope-intercept form [ y = mx + b ].

y - 6 = 4(x + 5)

y - 6 = 4x + 20

y = 4x + 26

We know that b = y-intercept for the y-intercept is 26.

Substitute 0 for y to find the x intercept.

0 = 4x + 26

-26 = 4x

-6.5 = x

Best of Luck!

7 0

3 years ago

Use the drop-down menus to choose steps in order to correctly solve 4k−6=−2k−16−2 please help just need steps

luda_lava [24]

4k-6=-2k-16-2
4k-6=-2k-18
6k-6=-18
6k=-12
k=-2

3 0

2 years ago

Which expression is equivalent to 174 :

Archy [21]

174 is equal to 174 if thats what the last one means

8 0

3 years ago

The Better Baby Buggy Co. has just come out with a new model, the Turbo. The market research department predicts that the demand

dlinn [17]

Answer:

$68

Step-by-step explanation:

We have been given the demand equation for Turbos as $q=-4p+544$ , where q is the number of buggies the company can sell in a month if the price is $p per buggy.

Let us find revenue function by multiplying price of p units by demand function as:

Revenue function: $pq=p(-4p+544)$

$pq=-4p^2+544p$

Since revenue function is a downward opening parabola, so its maximum point will be vertex.

Let us find x-coordinate of vertex using formula $\frac{-b}{2a}$ .

$\frac{-b}{2a}=\frac{-544}{2\times -4}$

$\frac{-b}{2a}=\frac{-544}{-8}$

$\frac{-b}{2a}=68$

The maximum revenue would be the y-coordinate of vertex.

Let us substitute $x=68$ in revenue formula.

$pq=-4(68)^2+544(68)$

$pq=-4*4624+544(68)$

$pq=-18496+36992$

$pq=18496$

Therefore, the company should sell each buggy for $68 to get the maximum revenue of $18,496.

8 0

3 years ago