#1. 4:7 8:14 12:21
#2. 5:7 10:14 15:21
#3. 9:7 18:14 27:21
#4. 11:2 22:4 33:6
#5. 7:21 14:42 21:63
#6. 7:5 14:10 21:15
#7. Equals
#8. Equals
#9. Equals
#10 not equal
#11 not equal
# 12. Equals
#13. y=20
#14. y=14
#15. y=15
#16. y=40
#17. y=40
#18. y=36
2x + 3y/4 = 5....multiply everything by 4
8x + 3y = 20
3y = -8x + 20
y = -8/3x + 20/3 or y = (-8x + 20) / 3
Answer: 
<u>Step-by-Step Explanation:</u>
Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

Note: hypotenuse not needed for tan

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10
1) 5.1
2)7.9
3) 4
4)20
5)8.9
6) 4.2
7)5.2
8)15
I'am somewhat confident that some are right because iam not sure your suppose to round the nearst tenth
B. Yes, (1,4) is a solution