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3 years ago

Three more than the product of a number and 8 is 6

Mathematics

2 answers:

Morgarella [4.7K]3 years ago

8 0

Answer:

x= $\frac{3}{8}$

Step-by-step explanation:

The sentence in number form is 8x+3=6

Solving for x.

You use inverse operations to cancel out the 3 on the left side.

What you do on one side of the equal sign you must do to the other side.

8x+3-3=6-3

Thus, you are left with 8x=3.

The inverse operation you use next to get x by itself is division. This cancels out the 8 on the left.

$\frac{8x}{8}$ = $\frac{3}{8}$

You are left with x= $\frac{3}{8}$

Nat2105 [25]3 years ago

6 0

Answer:

3 > x * 8 = 6

Step-by-step explanation:

three (3) more than ( > ) the product ( * ) of a number (x) and 8 (8) is (=) 6

Hope this helps :)

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H (x) =-x-1 find h (6)

bezimeni [28]

h(6)=-7

Step-by-step explanation:

replace x with 6

-(6) -1

-6 + -1

-7

6 0

3 years ago

Find all the zeros of the equation. -x^3-3x^2=6x+4

k0ka [10]

Answer:

The zeros of given expression $-x^3-3x^2=6x+4$ is -1, $-1+i\sqrt{3}$ and $-1-i\sqrt{3}$

Step-by-step explanation:

Given expresssion is $-x^3-3x^2=6x+4$

To find zeros of given expression we have to equate the expression to zero.

ie., $-x^3-3^2-6x-4=0$

$-(x^3+3x^2+6x+4)=0$

$x^3+3x^2+6x+4=0$

By using synthetic division

-1 | 1 3 6 4

| 0 -1 -2 -4

|________________

1 2 4 0

Therefore (x+1) is a zero

Now the quadratic equation is $x^2+2x+4=0$

For quadratic equation $ax^2+bx+c=0$ we have

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here a=1 ,b=2 and c=4 now substitute the values

$x=\frac{-2\pm \sqrt{2^2-4(1)(4)}}{2(1)}$

$x=\frac{-2\pm \sqrt{4-16}}{2}$

$x=\frac{-2\pm \sqrt{-12}}{2}$

$x=\frac{-2\pm \sqrt{12i^2}}{2}$ where $i^2=-1$

$x=\frac{-2\pm i \sqrt{4\times 3}}{2}$

$x=\frac{-2\pm i \sqrt{4}\sqrt{3}}{2}$

$x=\frac{-2\pm 2i\sqrt{3}}{2}$

$x=2\times\frac{(-1\pm i\sqrt{3})}{2}$

$x=-1\pm i\sqrt{3}$

Therefore $x=-1+i\sqrt{3}$ and $x=-1-i\sqrt{3}$

Therefore the zeros are -1, $-1+i\sqrt{3}$ and $-1-i\sqrt{3}$

4 0

4 years ago

Can someone help me with this question

natali 33 [55]

Answer: 5.5, 2, 196

Step-by-step explanation:

7 0

3 years ago

A party rental company has chairs and table for rent .the total cost to rent 2 chairs and 3 tables is $29 .the total cost to ren

jarptica [38.1K]

Let C = cost to rent each chair

Let T = cost to rent each table

4C + 8T = 73

2C + 3T = 28

Multiply the 2nd equation by (-2) and then add the equations together

4C + 8T = 73

-4C - 6T = -56

2T = 17

T = 17/2 = 8.5

Plug this in to the 1st equation to solve for C

4C + 8(17/2) = 73

4C + 68 = 73

4C = 5

C = 5/4 = 1.25

So the cost to rent each chair is $1.25 and the cost to rent each table is $8.50

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3 years ago

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lapo4ka [179]

C) 22

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*5 Or more, raise the score*
(rounds to 22)
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4 years ago