The two linear equations represented in system A as :
3 x + 2 y =3 -------(1)
- 2 x - 8 y = -1 ------(2)
(1) × 2 + (2) × 3 gives
⇒ 6 x + 4 y - 6 x - 24 y = 6 -3
⇒ - 20 y = 3
⇒ y = 
Putting the value of y in equation (1), we get
Two linear equation represented in system B is:
3. -x - 14 y =1
4. - 2 x - 8 y = -1
-2 ×Equation (3) + Equation (4)=
2 x +28 y- 2 x - 8 y= -2 -1
⇒ 20 y = -3
⇒y =
Putting the value of y in equation (3),we get
As Two system , that is system (A) and System (B) has same solution.
By looking at all the options , i found that Option (D) is correct. The two system will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 2 times the second equation of System A.
The answer is 29 classmates.
-Blue has 7 people
-Brown has 15 people
-Green has 4 people
-Hazel has 3 people
When all added up 29 classmates.
Answer:
Multiplier = 1.75x (7/4).
7/8 cups butter, 4 and 3/8 ounces chocolate, 1 and 3/4 cups sugar, 7/8 teaspoons vanilla, 3 and 1/2 eggs (4 if rounded!), 1 and 5/16 cups flour.
Step-by-step explanation:
The ingredient list is for 16 brownies, but you need to make 28. This means you have to make 1.75x the amount (28/16), so all ingredient quantities need to be multiplied by 7/4 (1.75 in fraction form).
Butter: 1/2 * 7/4 = 7/8 cups
Chocolate: 5/2 * 7/4 = 4 and 3/8 ounces
Sugar: 1 * 7/4 = 1 and 3/4 cups
Vanilla: 1/2 * 7/4 = 7/8 teaspoons
Eggs: 2 * 7/4 = 3 and 1/2 eggs (if rounded, 4, as 3.5 rounds up)
Flour: 3/4 * 7/4 = 1 and 5/16 cups
Answer:
ans is mean
Step-by-step explanation:
pls make me brainlest pls i beg you
Answer:
The sample size needed is 2401.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error of the interval is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.
We have to find n, for which M = 0.02.
There is no estimate of p available, so we use 
The sample size needed is 2401.
