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vesna_86 [32]
3 years ago
7

Tell whether – 7 is a solution of y + 14 > 2.

Mathematics
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

y>-12

Step-by-step explanation:

y+14>2

y+14-14>2-14

y>-12

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The table below shows 10 data values:
andrezito [222]
It would be d , because the lowest number which is your (min) is 72 the highest number which is your (max) is 93 . Your median would be 85 because you would add 84 & 86 and in result you would get 170 then you would divide by 2 and get 85 . Your Q1 would be 76 and your Q3 would be 91 , there is 10 numbers in total separate them (72,74,76,83,84) and (86,89,91,92,93) then find the middle number in each

Hope this helps !
7 0
3 years ago
Help asap my last question GIVING BRAINLIST!!!!
Alex

Answer:

1) x < 0

2) x > 0

3) x < 10

4) x < -\frac{31}{55}

5) x \geq 0

6) x \geq -1

Step-by-step explanation:

1) -3 > 2x -3

2x- 3 < -3

2x - 3 + 3 < -3 +3

2x < 0

\frac{2x}{2} < \frac{0}{2}

x < 0

2) 5 > -x + 5

-x + 5 < 5

- x + 5 -5 < 5 - 5

-x < 0

\frac{-x}{-1} < \frac{0}{-1}

x > 0

3) \frac{x}{5} -2 < 0

5 \times (\frac{x}{5} - 2 ) \times 5 < 0

x - 10 < 0

x -10 + 10 < 0 +10

x < 10

4) -5x + 11 > 31

-5x \cdot 11 < 31

-55x < 31

\frac{-55x}{-55} > \frac{31}{-55}

x < -\frac{31}{55}

5) \frac{1}{2}x - 4 \geq -4

\frac{1}{2}x -4 +4 \geq -4 +4

\frac{1}{2}x \geq 0

\frac{\frac{1}{2}x }{\frac{1}{2} } \geq \frac{0}{\frac{1}{2} }

x \geq 0

6) -4x + 2 \leq 6

-4x +2 - 2 \leq 6 -2

-4x < 4

\frac{-4x}{-4} \leq  \frac{4}{-4}

x \geq -1

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Step-by-step explanation:

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