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Mashutka [201]
2 years ago
10

In how many map squares did we spot less than 20 plant species help plssss

Mathematics
1 answer:
IRINA_888 [86]2 years ago
7 0

Answer:

two map squares ☺️☺️☺️☺️

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What is 0.08 10 times as much
RSB [31]
Well...
0.08
X 10
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????

0.80
3 0
3 years ago
What fraction is equivalent to 30/360?
Firdavs [7]

Answer:

1/12

Step-by-step explanation:

Given that

30/360 to lowest fraction equivalent

Now, we can write 30 as 3×10

Also, we can write 360 as 36×10

Then, we have

(3×10)/(36×10)

Then, 10 cancel 10, we are left with

3/36

Also we can write 36 as 12×3

Then, we have

3/(12×3)

Also, 3 cancel 3, we are left with

1/12

Then the lowest fraction is 1 / 12

1/12

4 0
2 years ago
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You invest $1000
Shkiper50 [21]

i dont speak English 3456

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2 years ago
A Cab charges $1.75 for the flat fee and $0.25 for each mile. Write and solve an inequality to determine how many miles Eddies c
NemiM [27]
1.75 + 0.25x ≤ 15
where x is equal the number of miles.

The key to solving an inequality is just temporarily making the ≤ symbol a =. Then solve for x like any other algebraic equation. Once you find the value of x, you will have solved the inequality. Make sure to add back the ≤ when you are done. 

15 - 1.75 = 13.25
13.25/0.25 = x 
x = 53
add back the ≤
x ≤ 53
This means Eddies can travel up to 53 miles with his $15.
4 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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