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max2010maxim [7]
2 years ago
14

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPp

Mathematics
2 answers:
aalyn [17]2 years ago
6 0

Answer:

The answer is 36 ft²

Step-by-step explanation:

Let us divide this whole figure into 2 rectangle, a big and a small.

Rectangle 1: (Small)

  • Length (l) = 2 ft
  • Breadth (b) = 3 ft

(Area 1) = l × b

A = 2 × 3 = 6 square ft

Rectangle 2: (Big)

  • Length (l) = 6 ft
  • Breadth (b) = 5 ft

(Area 2) = l × b

A = 6 × 5 = 30 square ft

Now,

Total Area of figure = Area of Rectangle 1 + Area of Rectangle 2.

Total Area = 6 + 30 = 36 square ft.

Thus, The area of the figure is 36 ft².

love history [14]2 years ago
3 0

Answer:

<u>36 in²</u>

Step-by-step explanation:

<u>Area of the figure</u>

  • Area (small rectangle) left + Area (big rectangle) right
  • 3 x (6 - 4) + 5 x 6
  • 3 x 2 + 30
  • 6 + 30
  • <u>36 in²</u>

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C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature
Alona [7]

Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

5 0
3 years ago
Y = 4x + 3 how do you solve this
laiz [17]

Answer:

You cannot gather an answer from this, it is in simplest form

5 0
3 years ago
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Plz help and if u don't know then don't answer
Anon25 [30]
We see a right triangle here.
Use the Pythagorean Theorem:
a^2+b^2=c^2
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a^2=175
a=13.2287565553
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2 years ago
A family of 8 goes to the amusement park. Each ride at the park costs 1 ticket per person. If they all go on every ride together
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Tju [1.3M]
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For example, we could have \mathbf u=(0,1) and \mathbf v=(0,-1). Any vector \mathbf w of the form (r,0), where r\neq0, is impossible to obtain as a linear combination of these \mathbf u and \mathbf v, since

c_1\mathbf u+c_2\mathbf v=(0,c_1)+(0,-c_2)=(0,c_1-c_2)\neq(r,0)

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