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3 years ago

Designing the right elements for the tasks that the user is attempting to perform is called ________.

Computers and Technology

1 answer:

skelet666 [1.2K]3 years ago

6 0

Answer:

Interface design

Explanation:

INTERFACE DESIGN are design that are carried out on either a computer or a mobile phone or other devices that will suit the users by designing the style of the devices and how the device will look like which will inturn enable the user to easily carried out or performed any tasks they are want to perform with easy and without any lapses which is why it is important for INTERFACE DESIGN to be design with the right tools that the user can easily understand in order to access and perform their tasks effectively.

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PLEASE HELP what is the mechanical advantage of a wheel with a radius of 8.0 cm connected with a axle with a radius of 2.5 cm?

Paraphin [41]

3.2 i believe. I looked it up though

5 0

4 years ago

Read 2 more answers

Question 2 In this question you are asked to calculate probabilties for the discrete uniform and exponential distribution. Make

sasho [114]

Answer:

Hi there! The question is asking to make changes to the H3_Q2.java program however there is no such program attached. Nevertheless, the requirements in the question can be addressed in a new H3_Q2.java program that i've listed below.

Explanation:

We can use the Scanner util in Java for prompting user input. The method nextInt() and nextDouble() allow only values of types "int" and "double" respectively. I have used the "switch" statement to direct the program based on user selection of menu item. The checks are printed with the "System.out.println" command and the program exits in case of error or invalid input. Finally, the calculation of probability simply requires you to replace the comment with the formula for the probability calculation based on the method chosen.

H3_Q2.java

import java.util.Scanner;

public class H3_Q2 {

public static void main(String args[]) {

// print main menu for user selection

System.out.println("Please type 1 to select 'discrete uniform' or 2 to select 'exponential'");

Scanner scan = new Scanner(System.in);

int selection = scan.nextInt();

switch(selection) {

case 1:

// discrete uniform

System.out.println("Please enter a lower bound value a: ");

int a = scan.nextInt();

System.out.println("Please enter a upper bound value b: ");

int b = scan.nextInt();

System.out.println("Please enter a value x: ");

int x = scan.nextInt();

if (b <= a) {

System.out.println("The upper bound value b should be greater than the lower bound value a");

System.exit(0);

}

if (a > x) {

System.out.println("The value x should be greater than the lower bound value b");

System.exit(0);

}

if (b < x) {

System.out.println("The value x should be greater than the lower bound value b");

System.exit(0);

}

break;

case 2:

// exponential

System.out.println("Please enter a lambda value for exponential: ");

double lambda = scan.nextDouble();

System.out.println("Please enter a value x: ");

double d_x = scan.nextDouble();

if (d_x <= 0.0) {

System.out.println("The value x should be greater than 0");

break;

} else {

// calculate P(X = x) and P(X ≤ x)

// result = calculateExponential()

System.out.println("The calculation for the exponential method given the lambda value " + lambda + " and the value of x " + d_x + " is: ");

}

break;

default:

System.out.println("Invalid input. Exiting..");

break;

}

7 0

3 years ago

The economist George gilder argued that

Vera_Pavlovna [14]

Answer: Lower taxes would result in greater economic growth.

Explanation: My teacher just gave me the answer on Apex

4 0

3 years ago

Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec

kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0

3 years ago

Write a function named repeat_words that takes two string parameters: 1. in_file: the name of an input file that exists before r

madam [21]

Answer:

#section 1

def repeat_words(firstFile, secondFile):

infile_1=open(firstFile,'r')

content1=infile_1.read()

infile_1.close()

#section 2

import string

newContent=""

for char in content1:

newContent+=char.strip(string.punctuation)

newContent=newContent.lower()

newContent=newContent.split()

#section 3

repeated_list=[]

for word in newContent:

if newContent.count(word)>1:

repeated_list.append(word)

#section 4

new_repeat_list=[]

for item in repeated_list:

while item not in new_repeat_list:

new_repeat_list.append(item)

#section 5

outfile=open(secondFile,'w')

for repeat in new_repeat_list:

outfile.write(repeat)

outfile.write('\n')

outfile.close()

infile_2=open(secondFile,'r')

content2=secondFile.read()

infile_2.close()

return content2

# section 6

in_file = 'aa.txt'

out_file = 'cpu.txt'

print(repeat_words(in_file, out_file))

Explanation:

#section 1

it defines a function that takes two arguments. It opens the first argument in the read mode and stores all it's content in a string variable "content1". finally the file is closed.

#section 2

In this section the string module is imported which allows for easy manipulation of string variables.

A new string variable is created that would store the already stripped file.

strip(string.punctuation) strips every character of any leading or trialing punctuation.

lower() converts string to lover case.

split() converts a string to an array of sub-string, i.e an array of words.

#section 3

This section collects all the words in the array and places them in a list.

#section 4

Utilizes a For and a While loop to ensure that no word repeats and stores it in a new list.

#section 5

Opens a new file and writes all the content into that new file and then closes the file.

re-opens the file, reads and returns the content of the file.

# section 6

This is added in order to test the function and print the result

I used your question to test the function and attached the result.

cheers!

8 0

3 years ago